c - 警告 : cast to pointer from integer of different size [-Wint-to-pointer-cast] c programming

Question

我不明白为什么会触发这个警告!

test.c:920:56:警告:从不同大小的整数转换为指针 [-Wint-to-pointer-cast]

if((memcpy((void *)(buffer_post_offset + 位置), (void *) data_block_n, bytes_to_write)) == NULL){

这是一段代码...

    char *buffer_post_offset = NULL;        

    // ....

    // Gets the data between offset and size        
    for(i = 0, data_block_n = start_at, position = 0, bytes_to_write = 0; data_block_n <= finish_at; ++data_block_n, ++i, position += bytes_to_write){

        // Gets from disk the sector/block of data
        if(Disk_Read(data_block_n, sector_str_data) == FAIL){
            osErrno = E_GENERAL;
            return FAIL;        
        }

        // Calculates how many bytes are to be written
        bytes_to_write = SECTOR_SIZE;
        if(data_block_n == finish_at)
            bytes_to_write -= inode.size - open_files_table.table[fd]->offset % SECTOR_SIZE;                 

        // Gets more memory for the buffer
        if((buffer_post_offset = (void *) realloc((void *) buffer_post_offset, (i + 1) * bytes_to_write * sizeof(char))) == NULL){
            osErrno = E_GENERAL;
            return FAIL;                        
        }

        // Writes into the buffer that store the data between offset and size

        // GETTING THE WARNING ON THE NEXT LINE !!!!!!

        if((memcpy((void *) buffer_post_offset + position, (void *) data_block_n, bytes_to_write)) == NULL){
            osErrno = E_GENERAL;
            return FAIL;        
        }
    }

Answer 1

sizeof (int) 可能与 sizeof(void*) 不同，使用 std::uintptr_t 将指针保存在整数中。