我有一个包含 double
值(20 行和 4 列)的 csv
文件,我想读取该文件并将这些值存储在缓冲区中以执行某些操作。我的以下实现在屏幕上显示了一些字符。我试图查看问题出在哪里,但我不知道问题出在哪里:
#include<stdio.h>
#include <stdlib.h>
#include<String.h>
int main()
{
char buff[80];
double buffer[80];
char *token = NULL;
FILE *fp = fopen("dataset.csv","r");
if(fp == NULL){
printf("File Reading ERROR!");
exit(0);
}
int c = 0;
do
{
fgets(buff, 80, fp);
token = strtok(buff,",");
while( token != NULL )
{
buffer[c] = (char) token;
token = strtok(NULL,",");
c++;
}
}while((getc(fp))!=EOF);
for(int i=1; i<=80; ++i){
printf("%c ", buff[i]);
if(i%4 == 0) printf("\n");
}
}
感谢任何帮助。
最佳答案
不错的尝试,稍微修改一下,如下所示:
#include <stdio.h>
#include <stdlib.h>
#include <string.h> // not String.h
int main(void)
{
char buff[80];
double buffer[80] = {0}; // I like initialization my arrays. Could do for 'buff' too
char *token = NULL;
FILE *fp = fopen("dataset.csv","r");
if(fp == NULL){
printf("File Reading ERROR!");
exit(0);
}
int c = 0;
while(fgets(buff, 80, fp) != NULL) // do not use 'getc()' to control the loop, use 'fgets()'
{
// eat the trailing newline
buff[strlen(buff) - 1] = '\0';
token = strtok(buff, ",");
while( token != NULL )
{
// use 'atof()' to parse from string to double
buffer[c] = atof(token);
token = strtok(NULL,",");
c++;
}
}
// print as many numbers as you read, i.e. 'c' - 1
for(int i=1; i<=c - 1; ++i) // be consistent on where you place opening brackets!
{
printf("%f\n", buffer[i]);
}
// Usually, we return something at the end of main()
return 0;
}
示例运行:
C02QT2UBFVH6-lm:~ gsamaras$ cat dataset.csv
3.13,3.14,3.15,3.16
2.13,2.14,2.15,2.16
C02QT2UBFVH6-lm:~ gsamaras$ ./a.out
3.140000
3.150000
3.160000
2.130000
2.140000
2.150000
2.160000
注释:
- 使用atof()到 从 c 中的字符串解析为 double .
- 我们通常更喜欢 fgets() over getc() .
关于c - 读取 csv 文件并存储在缓冲区中时出现问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39309993/