这段代码正在读取一个文本文件并将每个单词插入到链接列表中。 我是链表新手,现在已经为此工作了四个小时,但我一生都无法弄清楚这一点。
那么这是怎么回事呢?我已经检查了我知道的所有方法,但我一生都无法正确打印链接列表。我相信它与 push
/append
函数有关。不知何故,它覆盖了链接列表中以前的所有内容。也许 printlist 函数会覆盖所有内容,但我不明白它是如何做到这一点的。
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
// A complete working C program to demonstrate all insertion methods
// on Linked List
// A linked list node
struct Node;
void push(struct Node **head_ref, char *new_data);
void insertAfter(struct Node *prev_node, char *new_data);
void append(struct Node **head_ref, char *new_data);
void printList(struct Node *node);
int LINECOUNT(FILE *(*stream), char *filename);
struct Node {
char *data;
struct Node *next;
};
/* Given a reference (pointer to pointer) to the head of a list and
an int, inserts a new node on the front of the list. */
void push(struct Node **head_ref, char *new_data) {
/* 1. allocate node */
struct Node* new_node = (struct Node *)malloc(sizeof(struct Node));
/* 2. put in the data */
new_node->data = new_data;
printf("push data:%s ", new_data);
/* 3. Make next of new node as head */
new_node->next = (*head_ref);
/* 4. move the head to point to the new node */
(*head_ref) = new_node;
}
/* Given a reference (pointer to pointer) to the head
of a list and an int, appends a new node at the end */
void append(struct Node **head_ref, char *new_data) {
/* 1. allocate node */
struct Node* new_node = (struct Node *)malloc(sizeof(struct Node));
struct Node *last = *head_ref; /* used in step 5*/
/* 2. put in the data */
new_node->data = new_data;
printf("push data:%s ", new_data);
/* 3. This new node is going to be the last node, so make next of
it as NULL*/
new_node->next = NULL;
/* 4. If the Linked List is empty, then make the new node as head */
if (*head_ref == NULL) {
*head_ref = new_node;
return;
}
/* 5. Else traverse till the last node */
while (last->next != NULL)
last = last->next;
/* 6. Change the next of last node */
last->next = new_node;
return;
}
// This function prints contents of linked list starting from head
void printList(struct Node *node) {
while (node != NULL) {
printf(" %s ", node->data);
node = node->next;
}
}
int LINECOUNT(FILE *(*stream), char *filename) {
int size = 0;
size_t chrCount;
char *text;
if ((*stream = fopen(filename, "r")) == NULL) {
printf("LC Could not open hw8 data file.\n");
exit(0);
}
while (1) {
text = NULL;
getline(&text, &chrCount, *stream);
free(text); /*free text*/
if (feof(*stream))
break;
size++;
}
rewind(*stream);
return size;
}
/*int wordCount(FILE *(*stream), char *filename, int lineCount) {
char ch;
int wordcount = 0;
int charcount = 0;
*stream = fopen(filename, "r");
int x = 0;
int lineArr[lineCount];
for (int i = 0; i < lineCount; i++) {
lineArr[i] = 0;
}
if (*stream) {
while ((ch = getc(*stream)) != EOF) {
if (ch != ' ' && ch != '\n') {
charcount++;
}
if (ch == ' ' || ch == '\n') {
wordcount++;
lineArr[x] = lineArr[x] + 1;
}
if (ch == '\n') {
x++;
}
}
if (charcount > 0) {
wordcount++;
charcount++;
}
} else {
printf("Failed to open the file\n");
}
// rewind(*stream);
return lineArr;
}*/
int main(void) {
char *fn = "hw8data.txt";
int lineCount;
FILE *stream;
lineCount = LINECOUNT(&stream, fn);
//int lineArr[lineCount];
//int lineArr[];//lineArr[0] = 4 would say the first line has 4 words. using this data for strtok
//lineArr = wordCount(&stream, fn, lineCount);
//-------------------------------------
char ch;
int wordcount = 0;
int charcount = 0;
stream = fopen("./hw8data.txt", "r");
int x = 0;
int lineArr[lineCount];
for (int i = 0; i < lineCount; i++) {
lineArr[i] = 0;
}
if (stream) {
while ((ch = getc(stream)) != EOF) {
if (ch != ' ' && ch != '\n') {
charcount++;
}
if (ch == ' ' || ch == '\n') {
wordcount++;
lineArr[x] = lineArr[x] + 1;
}
if (ch == '\n') {
x++;
}
}
//if (charcount > 0) { wordcount++; charcount++; }
} else {
printf("Failed to open the file\n");
}
/* Start with the empty list */
struct Node *head = NULL;
rewind(stream);
char *sArr = malloc(42 * sizeof(char));
fscanf(stream, "%s ", sArr);
printf("%s ", sArr);
push(&head, sArr);
fscanf(stream, "%s ", sArr);
printf("%s ",sArr);
append(&head, sArr);
printList(head);
return 0;
}
最佳答案
char* sArr=malloc(42*sizeof(char));
fscanf(stream,"%s ",sArr);
printf("%s ",sArr);
push(&head,sArr);
fscanf(stream,"%s ",sArr);
printf("%s ",sArr);
append(&head,sArr);
您将相同的值添加到列表中两次,这是您从一次返回的值,并且仅调用malloc
。如果您希望两个节点保存不同的值,请不要将相同的值添加两次。一个丑陋的修复是,如果在 push(&head,sArr)
之后添加另一个 sArr = malloc(42*sizeof(char));
。这样,您对 append
的调用就会向列表添加不同的值。
如果您没有看到此内容,请添加代码以在打印列表时输出 node->data
的值。您将看到两个节点都有指向同一 block 内存的指针,即您从调用 malloc
中返回的值。
但是如果您的列表条目拥有其内容,那就更优雅了。这需要像 push
和 append
这样的函数来分配自己的指针,将字符串复制到其中,然后使用这些新指针。销毁列表的代码可以对指向的数据以及节点调用free
。
关于c - 我的链接列表正在打印文本文件中所有元素的最后一个单词,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52911257/