#include <stdio.h>
int multiple(int num1,int num2){
return (num1*num2);
}
int add(int num1, int num2){
return (num1+num2);
}
/*&x points to its value space *x points to its memory space*/
int main(){
int num1,num2,ans;
char func;
printf("First number => ");
scanf("%d",&num1);
printf("Second number => ");
scanf("%d",&num2);
printf("Please Enter + for addition, or * for multiplication => ");
scanf("%c",&func);
if (func == '*'){
ans = multiple(num1,num2);
}else if(func == '+') {
ans = add(num1,num2);
}else {
printf("Sorry, invalid operation");
}
printf("Ans : %d",ans);
return 0;
}
当我运行程序时,它会提示我输入第一个和第二个数字,但它不会提示我输入字符 scanf("%c",&func);
没有被执行。
我的输出-------------------------------------------------------- --------------------:
$ ./p8t3
First number => 23
Second number => 32
Please Enter + for addition, or * for multiplication => Sorry, invalid operationAns : 2665616
最佳答案
在扫描 + 或 * 运算符时,进行如下更改:
printf("Please Enter + for addition, or * for multiplication => ");
scanf(" %c",&func); //use a space before '%c'
关于c - 当使用 scanf 获取整数和 char 值时,程序会跳过 scanf,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17631851/