c - 如何在C中解析一行整数

Question

我想对以下测试文本文件中的每个整数进行非常基本的读取。

1 2 3 4 5
6 7 8 9 10

但是在我正确打印第一行后，以下代码无限打印 1。

FILE* f;
uint32_t current_row = 0;
uint32_t current_col = 0;
char line[1024];
int value; // issues with printing uint32_t right now

// Open the file
f = fopen("blah.txt", "r");
if (f == NULL) {                                                               
  fprintf(stderr, "file could not be opened.\r\n");                    
  exit(ERROR_FILEPATH);                                                        
}

// Read in each row
while (NULL != fgets(line, sizeof(line), f)) {
  printf("%d: %s\r\n", current_row, line);

  // Read in each integer in the current row 
  while (sscanf(line, "%d", &value) {
    printf("%d\t", value);
    // TODO: How to read a single integer in at a time?
    current_col++;
  }

  current_col = 0;
  current_row++;
}

// Close the file                                                              
if (fclose(f)) {                                                      
  fprintf(stderr, "file could not be closed.\r\n");                      
  exit(ERROR_FILECLOSE);                                                       
}

Answer 1

而不是:

  // Read in each integer in the current row 
  while (sscanf(line, "%d", &value) {
    printf("%d\t", value);
    // TODO: How to read a single integer in at a time?
    current_col++;
  }

就我个人而言，我不喜欢“scanf”函数系列:

  // Read in each integer in the current row 
  char *cp = line;
  while(*cp && *cp != '\n') 
    {
    /* skip leading white space. */
    while(isspace(*cp))
       ++cp;

    /* Read the next number. */   
    value = strtol(cp, &cp, 10);
    printf("%d\t", value);

    current_col++;
    }