c - 在链表的 "struct name *next"内添加 "struct name"的目的是什么？我的意思是我实际上无法处理到底发生了什么

Question

#include<stdio.h>
#include<stdlib.h>

typedef struct employ
{
    int reg;
    int sal;
    char *name;
    struct employ *next; // I want to know the purpose of this line
}EMP;

int main(void)
{
    EMP *first,*emp1,*emp2,*emp3,*ans;
    first = (EMP *)malloc(sizeof(EMP));
    first->next = NULL;
    /////first///////
    emp1 = (EMP *)malloc(sizeof(EMP));
    if(emp1 == NULL)
    {
        perror("malloc error");
        exit(1);
    }

    emp1->reg = 100;
    emp1->sal = 30000;
    emp1->name = "james";
    emp1->next = first;
    first = emp1;

    /* I havent completed the program bcoz its not necessary here */

Answer 1

在链表中，每个节点都包含一个指向下一个节点的指针。

struct employ *next;

用于实现该效果

+---------+        +---------+
|  Node1  |------->|  Node2  |----> ...  
+---------+        +---------+

如果你在node1，next是一个指向node2的指针，这样你就可以从当前元素访问下一个元素