c - scanf期间C中的段错误

Question

我正在尝试扫描一个整数以用于我的程序。但是，我的程序在编译期间给了我段错误，这是给我错误的部分:

int main(void)
{
    int totalHeight=0, floorWidth=0, amountOfStories, amountWindowForTop, amountWindowForMiddle, amountWindowForBottom, windowHeight, middleWindowWidth, topWindowWidth, bottomWindowWidth, minimumHeight, minimumWidth;

    char topFloorWindowContent, middleFloorWindowContent, bottomFloorWindowContent, windowBorder, floorBorder;

    int tempMax;

    printf("please enter how many stories your building would like to have: ");
    scanf("%d",&amountOfStories);
    minimumHeight=amountOfStories*6+1;
    while((totalHeight<minimumHeight)||((totalHeight%amountOfStories)!=1))
    {
        printf("please enter the totalHeight (minimum %d): ",minimumHeight);
        scanf("%d",&totalHeight);
    }
    printf("please enter how many window building would have for top floor: ");
    scanf("%d",amountWindowForTop);
    printf("please enter how many window building would have for middle floors: ");

现在我的程序编译后只运行到 amoutWindowForTop 上的 scanf 在我输入该值后，它只会给我段错误，我不知道为什么。因为我没有使用指针，所以为什么它会给我这个错误？一切对我来说似乎都很顺利 这是输出

please enter how many stories your building would like to have: 5
please enter the totalHeight (minimum 31): 31
please enter how many window building would have for top floor: 2
Segmentation fault

Answer 1

你错过了&在

scanf("%d",amountWindowForTop);

这一定是

scanf("%d",&amountWindowForTop);

错误原因是 & 被称为运算符地址，因此在 scanf 中缺少它意味着您将值放在哪里意味着地址是必需的，因为它指定了我们必须在其中保存值的变量的地址。 每当出现任何与地址相关的问题时，我们通常都会遇到段错误错误。 希望对您有用。