当我尝试 printf()
数据的值时,我什么也得不到,但如果我这样做 date = "text"
它就会起作用。有谁知道原因吗?
struct aac { char **data; };
int main ( ) {
char* value = malloc ( 100 );
strcpy ( value, "test" );
struct aac b;
b.data = malloc ( 100 );
cake ( value, &b );
donut ( &b );
return 0;
}
int cake ( char *value, struct aac *c ) {
c->data[0] = value;
return 0;
}
int donut ( struct aac *b ) {
printf ( "%s", b->data[0] );
return 0;
}
最佳答案
也许这个例子可能有帮助:
#include <stdio.h>
#include <string.h>
#include <malloc.h>
#include <errno.h>
struct aac {
char **pastries;
};
void
init_pastries (struct aac * rec_p, int max)
{
/* Allocate space for max #/pastries, plus a NULL delimiter */
int nbytes = sizeof (char *) * (max+1);
rec_p->pastries = (char **)malloc (nbytes);
memset (rec_p->pastries, 0, nbytes);
printf ("init_pastries: max #/pastries: %d, malloc: %d bytes...\n",
max, nbytes);
}
void
add_pastry (char * name, int i, struct aac *rec_p)
{
int nbytes = strlen (name) + 1;
rec_p->pastries[i] = (char *)malloc (nbytes);
strcpy (rec_p->pastries[i], name);
printf ("add_pastry (%s): malloc= %d bytes...\n",
name, nbytes);
}
void
print_pastries (struct aac * rec_p)
{
char **s = NULL;
for (s = rec_p->pastries; (*s); s++)
printf ("pastry: %s...\n", *s);
}
int
main ( ) {
struct aac rec;
init_pastries (&rec, 5);
add_pastry ("cake", 0, &rec);
add_pastry ("donut", 1, &rec);
print_pastries (&rec);
return 0;
}
这是示例输出:
gcc -o tmp tmp.c
./tmp
init_pastries: max #/pastries: 5, malloc: 24 bytes... add_pastry
(cake): malloc= 5 bytes... add_pastry
(donut): malloc= 6 bytes... pastry:
cake... pastry: donut...
“希望有帮助......至少有一点:)
关于C语言: structs and character arrays,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3562469/