这就是我尝试在 sqlite 数据库中添加数据的方法，一切正常，但数据没有添加到数据库中我不明白为什么你可以引用代码并告诉我我做错了什么
sqlite3_stmt *stmt;
int x;
char *update = "insert into PersonNamesAndBirthDates (Names,Birthdates,Phonenumber,Email,Profilepic) values(?,?,?,?,?);";
x = sqlite3_prepare_v2(database1, update, -1, &stmt, nil);
if (x == SQLITE_OK)
{
NSLog(@"PersonName is -->%@",[NSString stringWithFormat:@"%@",[_Namebarray objectAtIndex:0]]);
NSLog(@"BirthDates is -->%@",[NSString stringWithFormat:@"%@",[_Birthdatebarray objectAtIndex:0]]);
NSLog(@"BirthDates is -->%@",[NSString stringWithFormat:@"%@",[_Phonearray objectAtIndex:0]]);
NSLog(@"BirthDates is -->%@",[NSString stringWithFormat:@"%@",[_Emailarray objectAtIndex:0]]);
// if else will come here for checking weather images has added or not if added then store Yes Image if not then simply No image for default image.
sqlite3_bind_text(stmt, 1, [[NSString stringWithFormat:@"%@",[_Namebarray objectAtIndex:0]] UTF8String],-1, NULL);
sqlite3_bind_text(stmt, 2, [[NSString stringWithFormat:@"%@",[_Birthdatebarray objectAtIndex:0]] UTF8String],-1, NULL);
sqlite3_bind_text(stmt, 3, [[NSString stringWithFormat:@"%@",[_Phonearray objectAtIndex:0]] UTF8String],-1, NULL);
sqlite3_bind_text(stmt, 4, [[NSString stringWithFormat:@"%@",[_Emailarray objectAtIndex:0]] UTF8String],-1, NULL);
if(selectImage.image)
{
sqlite3_bind_text(stmt, 5, [[NSString stringWithFormat:@"%@",[_arrayOfPaths objectAtIndex:0]] UTF8String],-1, NULL);
}
else{
sqlite3_bind_text(stmt, 5, [[NSString stringWithFormat:@"%@",@"No Image"] UTF8String],-1, NULL);
}
}
if (sqlite3_step(stmt) != SQLITE_DONE){}
NSLog(@"Error: ");
sqlite3_finalize(stmt);
最佳答案
我在你的代码中没有看到任何错误，请检查你的数据库是否像这样打开
if (sqlite3_open(dbpath, &database1) == SQLITE_OK)
关于ios - 在sqlite数据库中插入数据的问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16186503/