c - 添加数组元素并存储在数组中

Question

这些代码从文件中获取数据并将其存储在数组中。然后它会搜索数组，如果数字在 0.5 到 50,000 之间(只是为了删除 0 和大数字)，则它会进入 if 语句。在此语句中，如果该数字等于下一个数字，它将检查另一个数组以过滤掉小数字和大数字，然后将其相加并将其存储到平均值并添加计数器。它会执行此操作，直到 array2 中的数字不等于它出现的下一个数字并计算其平均值等。

它做的一切都很好，直到达到mean[j] = Mean[j] + array1[i]，我尝试使用printf来检查该部分，它吐出一个巨大的负数。平均值数组与计数器一起设置为全零。请帮助:L

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(void)
{
  FILE *fp;
  float array1[1000], array2[1000], mean[1000], average[1000], counter[1000], range[1000], upper[1000], lower[1000];
  int a, h, i, r, j = 0, pos, found = 0, extrinsic[1000];
  int b=0;
  int linect = 1;
  char buf[128];
  extrinsic[100] = 0;
  mean[100] = 0;
  counter[100] = 0;
  range[100] = 0;
  upper[100] = 0;
  lower[100] = 0;
  average[100] = 0;
  i = 0;
  j = 0;
  fp = fopen("data.txt", "r");

  if(fp == NULL)
  {
    puts("Cannot open file for reading");
    scanf("%d", &a);
    exit(EXIT_FAILURE);
  }

  while( linect < 1000 ) 
    {
    fgets(buf, sizeof(buf), fp);
    sscanf(buf, "%f", &array1[i]);
    //printf("Set %d - 1st: %f\n", linect, array1[i]);
    linect++;
    i++;
    }
  fclose(fp);


  linect = 0; //reads lot data file and puts it in array2
  i = 0;
  fp = fopen("lot_numbers.txt", "r");
  if(fp == NULL)
  {
    puts("Cannot open file for reading");
    scanf("%d", &a);
    exit(EXIT_FAILURE);
  }
  while( linect < 1000 ) 
    {
    fgets(buf, sizeof(buf), fp);
    sscanf(buf, "%f", &array2[i]);
   // printf("Set %d - 1st: %f\n", linect, array2[i]);
    linect++;
    i++;
    }


  for (i = 0; i < 999; i++) //searches array sets repeated points to zero
  {
      if (array1[i] == array1[i+1])
      {
          array1[i] = 0;
          array2[i] = 0;
      }
  }
  for (i = 0; i < 9; i++)   //searches array
  {
      if (array2[i] > .5 && array2[i] < 50000)
      {
        if (array2[i] == array2[i+1])
        {
          if (array1[i] > .5 && array1[i] < 500){  //ignores zeros and junk data 
          mean[j] = mean[j] + array1[i];
          counter[j]= counter[j] + 1;
        }
      }
      else {
          average[j] = mean[j]/counter[j];
          range[j] = average[j] * 0.1;
          upper[j] = average[j] + range[j];
          lower[j] = average[j] - range[j];
          j++;
           }
      }
  }
  j = 0;
  while (j <10){
  printf("\n%f", mean[j]);
  j++;
  }
scanf("%d", &a);

return 0;
 }

Answer 1

我从未在 C: 中见过这种语法

平均值[100] = 0;

尝试使用标准 init 方法 How to initialize all members of an array to the same value?

平均值[100] = {0}；