你好,我是 C 语言新手,正在尝试编写一个程序,要求用户输入一大堆数字。我想循环 scanf
,以便它不断询问,当用户输入“0”时,它停止,读取输入的偶数和奇数,并分别对它们进行计数。现在,在用户按“Enter”键后,我可以继续询问新号码,但是当我输入“0”时,它只是不断询问更多号码并且不会停止。我究竟做错了什么?就像我之前说的,我很新,所以婴儿的话是最好的。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main (void) {
int number_of_integers, sum = 0, i, integer;
char user_name[128];
printf("What is your name?\n");
scanf("%s", user_name);
printf("\nEnter any real numbers followed by ENTER.\n");
while (integer != 0) {
scanf("%s", &integer);
if (integer == 0)
break;
}
printf("%s, the numbers you entered are broken down as follows:\n", user_name);
return 0;
}
最佳答案
正如评论者所指出的,我们不是家庭作业或辅导服务,但我通过制作一个我刚刚编造的实际工作示例来帮你一个忙。现在您可以根据自己的需求进行定制。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main (void) {
int max=100;
int integer;
int even[max];
int odd[max];
int index=0;
int evencount=0;
int oddcount=0;
char user_name[128];
printf("What is your name?\n");
scanf("%s", user_name);
printf("\nEnter any real numbers followed by ENTER.\n");
while (index < max){
scanf("%d", &integer);
if (integer == 0)
break;
if ((integer % 2) == 0){
evencount++;
even[evencount]=integer;
}else{
oddcount++;
odd[oddcount]=integer;
}
index++;
}
printf("%s, the %d numbers you entered are broken down as follows:\n", user_name,index);
printf("%d odd integer(s):\n",oddcount);
while (oddcount > 0){
printf("%d\n",odd[oddcount]);
oddcount--;
}
printf("%d even integer(s):\n",evencount);
while (evencount > 0){
printf("%d\n",even[evencount]);
evencount--;
}
return 0;
}
关于C 编程 - 重复 scanf 除非用户输入 "0",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32898787/