c - C 语言中的回溯迷宫算法一开始就是错误的

标签 c maze

过去一周我们一直在致力于这个项目。 除了初始化/分配和步骤函数之外的所有内容都是由我的教授预先提供给我的......

我们的目标不是创造迷宫,而是解决它。 我第一次编译它时,它似乎运行良好,并且会稍微通过它...然后,它会开始做一些时髦的事情,跳过一堵墙,然后停在那里...

尝试修复并解决它。最终它没有迈出现在应该迈出的第一步。试图理解我做错了什么或者为什么我现在没有做正确的第一步 在我的 maze_client...//已提供,但如果需要我可以更改一点

#include <stdio.h>
#include "maze.h"

int main(int argc, char **argv)
{
   FILE *fp = fopen(argv[1], "r");
   Maze maze = initializeMaze(fp);
   findPath(maze);// first step.. It was provided to me. It basically calls step() 
   displayMaze(maze);
   return 0;
}

Step 函数...我做了另一个不是 for 循环的函数,我试图看看是否也能摆脱这些废话。不起作用,只是让它在其他地方随机开始第一步...第二个文件完成了尝试,我屏蔽了每个函数...它似乎在我的 if(getBottom) 语句中。 .如果需要的话,我可以写下我想要它做什么的逻辑步骤......

static int step(Maze maze, int row, int column)
{
  //TODO: FINISH THE BACKTRACKING ALGORITHM
  int i,j;
  //int st;
  int successful;
 //maze->maze[row][column] = st;

 if(getVisit(maze, row, column) == maze->maze[maze->finishX][maze->finishY])
 {
   displayMaze(maze);
   return 1;
 }

 displayMaze(maze);
 getchar();
 // getVisit(maze, row, column);//gets pos
 for(i = -2; i <= 2; ++i)
 {
   for(j = -2; j <= 2; ++j)
   {
    //i*i != j*j dont move in diagonal
     //row+i >= 0 && row + i < n, bounds checking
     //col+j >= 0 && col+j < n, bounds checking
    if(i*i != j*j && row+i >= 0 && column+j >= 0 ) 
    {
      getVisit(maze, row, column);//Gets position 
        if(getCellHasTop(maze, row, column + 1) != 1)//Wall check, Zero meaning NO WALL
        {
                 //++st;
                 //gets that position and sees if it is unvisited... 
                 //need a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
                 if(getVisit(maze,row,column+j) == UNVISITED)
                 {
                    setVisit(maze, row, column+1, GOOD_PATH);
                  successful = step(maze, row, column + 1);
                 }
              // if(getVisit(maze, row, column+j) == GOOD_PATH)
              //   {
              //   setVisit(maze, row-i, column, BAD_PATH);
          //   successful = step(maze, row, column+j);
            //      }
                 if(successful)
                   return 1;  
        }
        if(getCellHasLeft(maze,row - 1,column) != 1)
        {
                 if(getVisit(maze, row-1, column) == UNVISITED)
                 {
                 setVisit(maze, row-1, column, GOOD_PATH);
                 successful = step(maze, row-1, column);
                 }

              //   if(getVisit(maze, row-i, column) == GOOD_PATH)
               //  {
              //setVisit(maze, row-i, column, BAD_PATH);
              // successful = step(maze, row-i, column);
               //  }
                 //++st;
                 if(successful)
                return 1;
        }
        if(getCellHasRight(maze,row + 1, column) != 1)
        {
                 if(getVisit(maze, row+1, column) == UNVISITED)
                 {
                  setVisit(maze, row+1, column, GOOD_PATH);
                  successful = step(maze, row+1, column);
                 }

               //  if(getVisit(maze, row+i, column) == GOOD_PATH)
  //               {
    //            setVisit(maze, row+i, column, BAD_PATH);
      //            successful = step(maze, row+i, column);
        //        }
                 //++st;
                 if(successful)
                return 1;
        }
        if(getCellHasBottom(maze, row, column - 1) != 1)
        {
                 if(getVisit(maze, row, column-1) == UNVISITED)
                 {
                  setVisit(maze, row, column-1, GOOD_PATH);
                  successful = step(maze, row, column-1);
                 }

      //           if(getVisit(maze, row, column-j) == GOOD_PATH)
        //       {
          //        setVisit(maze, row, column-j, BAD_PATH);
            //    successful = step(maze, row, column-j);
              //   }
                 //++st;
                 if(successful)
                return 1;  
        }  
        //PART 2
        //Do not do else if because then each one would require... That is last resort
    if(getCellHasTop(maze, row, column + 1) == 0)//Wall check
        {
                 //++st;
                 //a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH   
                 if(getVisit(maze,row, column+1) == GOOD_PATH)
               {
                  setVisit(maze, row, column, BAD_PATH);
                  successful = step(maze, row, column + 1);
                }
                if(successful)
              return 1;  
        }
       if(getCellHasLeft(maze,row - 1,column) == 0)
        {
                 if(getVisit(maze, row-1, column) == GOOD_PATH)
                 {
               setVisit(maze, row, column, BAD_PATH);
                successful = step(maze, row-1, column);
                }
   //++st;
               if(successful)
            return 1;
 }
if(getCellHasRight(maze,row + 1, column) == 0)
        {
                if(getVisit(maze, row+1, column) == GOOD_PATH)
                {
                 setVisit(maze, row, column, BAD_PATH);
                 successful = step(maze, row+1, column);
                }
                 //++st;
      if(successful)
     return 1;
       }
       if(getCellHasBottom(maze, row, column - 1) == 0)
   {
                if(getVisit(maze, row, column-1) == GOOD_PATH)
 {
                  setVisit(maze, row, column, BAD_PATH);
                  successful = step(maze, row, column-1);
                }
                 //++st;
                 if(successful)
              return 1;  
       }  
        //Part 3
       if(getCellHasRight(maze, row + 1, column) != 0 && getCellHasLeft(maze,row - 1, column) != 0)// If there is a wall at those locationsZZ
        {
                if(getVisit(maze,row, column+1) == BAD_PATH)
                 {
                 setVisit(maze, row, column, BAD_PATH);
      successful = step(maze, row, column-1); 
                 }
                 if(successful)
                return 1;
 }
       if(getCellHasTop(maze, row, column + 1) != 0 && getCellHasBottom(maze, row, column - 1) != 0)
   {
                 if(getVisit(maze, row-1, column) == BAD_PATH)
                 {
                 setVisit(maze, row, column, BAD_PATH);
                  successful = step(maze, row+1, column);
                }
               if(successful)
              return 1;
     }
        if(getCellHasTop(maze, row, column +1) != 0 && getCellHasBottom(maze, row, column - 1) != 0)
      {
              if(getVisit(maze, row+1, column) == BAD_PATH)
           {
         setVisit(maze, row, column, BAD_PATH);
             successful = step(maze, row-1, column);
              }
         if(successful)
      return 1;
       }
      }  
     } 
     }
      displayMaze(maze);
      getchar();
    return 0;
    }

最佳答案

我认为你的问题在于这样的代码:

    if(getCellHasTop(maze, row, column + 1) != 1)//Wall check, Zero meaning NO WALL
    {
             //++st;
             //gets that position and sees if it is unvisited... 
             //need a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
             if(getVisit(maze,row,column+j) == UNVISITED)
             {
                setVisit(maze, row, column+1, GOOD_PATH);
              successful = step(maze, row, column + 1);
             }
          // if(getVisit(maze, row, column+j) == GOOD_PATH)
          //   {
          //   setVisit(maze, row-i, column, BAD_PATH);
      //   successful = step(maze, row, column+j);
        //      }
             if(successful)
               return 1;  
    }

首先,您从 -2 迭代到 +2。但我认为迷宫单元是连续的,所以你不应该这样做。相反,做这样的事情: 首先,测试行、列以确保它们是迷宫中的有效位置。接下来,测试当前单元格的位,看看是否允许您向上或向任何方向移动。然后测试目标单元格是否有效。然后测试目标单元格是否被您已经经过的路径阻挡。然后跳进去。

enum {
    TOP_BLOCKED    = 0x01,
    RIGHT_BLOCKED  = 0x02,
    BOTTOM_BLOCKED = 0x04,
    LEFT_BLOCKED   = 0x08,
};

#define ABOVE(r,c)     (r),((c)+1)
#define BELOW(r,c)     (r),((c)-1)
#define LEFT_OF(r,c)   ((r)-1),(c)
#define RIGHT_OF(r,c)  ((r)+1),(c)

#define IN_MAZE(m,r,c) ((r)>=0 && (c)>=0 && (r)<(m)->rows && (c)<(m)->cols)
#define CELL(m,r,c) ((m)->maze[(r)][(c)])
#define TOP_OPEN(m,r,c) (in_maze(m, r, c) \
                        && !(CELL(m,r,c) & TOP_BLOCKED) 
                        && in_maze(m,ABOVE(r,c)))
#define VISITED(m,r,c) (getVisit(m,r,c) != UNVISITED)


// ... later, in your step function ...

#define POS  row,column

setVisit(maze, POS, GOOD_PATH);

if (TOP_OPEN(maze, POS) && !VISITED(maze, ABOVE(POS)) && step(maze, ABOVE(POS))) {
    // We found a successful path! Stop looking.
    return 1;
}

if (RIGHT_OPEN(maze, POS) ... && step(maze, RIGHT_OF(POS))) {
    return 1;
}

if (BOTTOM_OPEN ...

if (LEFT_OPEN ...
    return 1;
}

// There is no path from here that solves the maze.
setVisit(maze, POS, UNVISITED);
#undef POS

return 0;

关于c - C 语言中的回溯迷宫算法一开始就是错误的,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36795892/

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