我正在尝试创建一个 struct typedef movie_t
并将其添加到列表中。它包含标题、导演、评级和制作年份。我的代码只输出标题。我不明白为什么它不输出 movie_t
结构的所有成员?
例如,我定义了:
movie_t *first_movie = {"The Outsiders","Francis Ford Coppola",'PG13',1983}
但是当我运行我的程序时,它只输出标题:
list[0] = The Outsiders
list[1] = The Outsiders
list[2] = The Outsiders
list[3] = The Outsiders
list[4] = The Outsiders
list[5] = The Outsiders
list[6] = The Outsiders
list[7] = The Outsiders
list[8] = The Outsiders
list[9] = The Outsiders
basiclist.h
#ifndef BASICLIST_H_
#define BASICLIST_H_
typedef struct node {
void * data; /* pointer to data */
struct node * next; /* pointer to next next node */
} node_t;
int list_add(node_t ** list, void * data);
#endif
电影.h
#ifndef MOVIE_H
#define MOVIE_H
#define SIZE_LIMIT 25
#define RATING_SIZE 5
typedef enum {G, PG, PG13, R} rating_t;
typedef struct {
char rating;
char title[SIZE_LIMIT];
char director[SIZE_LIMIT];
int year;
}movie_t;
void get_movie(movie_t * movie);
void print_movie(const movie_t * movie);
#endif /* MOVIE_H */
main.c
#include "movie.h"
#include <stdlib.h>
#include <stdio.h>
#include "basiclist.h"
int list_add(node_t ** list, void * data) {
int ret = 0;
node_t * newnode = (node_t *) malloc(sizeof(node_t));
if (newnode == NULL) {
ret = -1;
}
else {
newnode->data = data;
newnode->next = *list;
}
*list = newnode;
return ret;
}
int main (void)
{
int ii;
movie_t * new_movie;
movie_t *first_movie = {"The Outsiders","Francis Ford Coppola",'PG13',1983};
node_t * list = NULL;
node_t * curr;
for(ii=0;ii<10;ii++) {
new_movie = (movie_t *) malloc(sizeof(int));
*new_movie = *first_movie;
list_add(&list, new_movie);
}
ii = 0;
curr = list;
while (curr != NULL) {
printf("list[%d] = %s\n", ii, *((movie_t *) curr->data));
ii++;
curr = curr->next;
}
printf("It worked!\n");
return 0;
}
最佳答案
printf("list[%d] = %s\n", ii, *((movie_t *) curr->data));
: movie_t
和movie_t*
不适合%s
。您为 move_t*
制作自定义打印功能(print_movie)。
诸如此类的东西
void print_movie(FILE* fp, const movie_t *m){
static const char *raiting[] = { "G", "PG", "PG13", "R"};
fprintf(fp, "%s\t%s\t%s\t%d\n", m->title, m->director, raiting[m->rating], m->year);
}
将原型(prototype) void print_movie(const movie_t * movie);
更改为 void print_movie(FILE* fp, const movie_t *m);
或更改姓名并从 print_movie
调用电话。
在主目录
更改 printf("list[%d] = %s\n", ii, *((movie_t *) curr->data));
到 print_movie(stdout, curr->data);
还有
更改 movie_t *first_movie = {"局外人","弗朗西斯·福特·科波拉",'PG13',1983};
至 movie_t first_movie = {"局外人","弗朗西斯·福特·科波拉", (char)PG13, 1983};
和
改变
typedef struct {
char rating;
char title[SIZE_LIMIT];
char director[SIZE_LIMIT];
int year;
}movie_t;
至
typedef struct {
char title[SIZE_LIMIT];
char director[SIZE_LIMIT];
char rating;//or rating_t rating;
int year;
}movie_t;
和
for(ii=0;ii<10;ii++) {
new_movie = (movie_t *) malloc(sizeof(int));//int !!
*new_movie = *first_movie;
list_add(&list, new_movie);
}
至
for(ii=0;ii<10;ii++) {
new_movie = malloc(sizeof(*new_movie));
*new_movie = first_movie;
list_add(&list, new_movie);
}
关于c - 将结构添加到列表并获得正确的输出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39823624/