c - 将数组值写入内存时遇到问题

Question

我正在使用带有 adafruit FRAM 内存突破的 arduino。我正在尝试获取以下内容以从数组中提取值，然后将它们保存到 FRAM 中。问题是保存的值不正确。需要进行什么转换才能存储这些值？

#include <Wire.h>        
#include "Adafruit_FRAM_I2C.h"        
String incomingData = "244,1,1,7,13,1,0";        


Adafruit_FRAM_I2C fram     = Adafruit_FRAM_I2C();        
uint16_t          framAddr = 0;        
void setup(void) {        

 Serial.begin(9600);        

  if (fram.begin()) {  // you can stick the new i2c addr in here, e.g. begin(0x51);        
    Serial.println("Found I2C FRAM");        
  } else {        
    Serial.println("I2C FRAM not identified \r\n");          
  }        

uint8_t input[16];        

incomingData.getBytes(input,16);        
uint8_t *str;        
int i_ctr;        
uint8_t arr[16][16];            

for(i_ctr = 0,str = strtok(input,","); str!= NULL; i_ctr++, str= strtok(NULL,","))        
  {        
    strcpy( arr[i_ctr], str);        
  }        


fram.write8(0x0, arr[0]);        
               fram.write8(0x1,  arr[1]);        
              fram.write8(0x2, arr[2]);        
fram.write8(0x3, arr[3]);        
               fram.write8(0x4, arr[4]);        
               fram.write8(0x5, arr[5]);        
               fram.write8(0x6, arr[6]);        
               fram.write8(0x7, 77); //test        

  Serial.println(fram.read8(0x0));        
  Serial.println(fram.read8(0x1));        
  Serial.println(fram.read8(0x2));        
  Serial.println(fram.read8(0x3));        
  Serial.println(fram.read8(0x4));        
  Serial.println(fram.read8(0x5));        
  Serial.println(fram.read8(0x6));        
    Serial.println(fram.read8(0x7));        

}        

输出:

218
234
250
10
26
42
58
77

Answer 1

arr[i] 是一个地址，你实际写入的是地址的低字节(看看打印的值是如何相隔 16 的)。如果您想获得传入数据的数值，请将代码更改为

    uint8_t arr[16];  // One dimension is enough
    for (....) {
        arr[i_ctr] = atoi(str);
    }

PS:你没有收到任何编译器警告吗？