我对 Kotlin lambda 语法感到困惑。
一开始我有
.subscribe(
{ println(it) }
, { println(it.message) }
, { println("completed") }
)
效果很好。
然后我将 onNext 移到另一个名为 GroupRecyclerViewAdapter 的类,它实现了 Action1<ArrayList<Group>>
.
.subscribe(
view.adapter as GroupRecyclerViewAdapter
, { println(it.message) }
, { println("completed") }
)
但是,我得到了错误:
Error:(42, 17) Type mismatch: inferred type is () -> ??? but rx.functions.Action1<kotlin.Throwable!>! was expected
Error:(42, 27) Unresolved reference: it
Error:(43, 17) Type mismatch: inferred type is () -> kotlin.Unit but rx.functions.Action0! was expected
我可以通过更改为来修复错误:
.subscribe(
view.adapter as GroupRecyclerViewAdapter
, Action1<kotlin.Throwable> { println(it.message) }
, Action0 { println("completed") }
)
有没有办法在不指定类型的情况下编写 lambda?(Action1<kotlin.Throwable>
,Action0
)
Note: subscribe is RxJava method
编辑 1
class GroupRecyclerViewAdapter(private val groups: MutableList<Group>,
private val listener: OnListFragmentInteractionListener?) :
RecyclerView.Adapter<GroupRecyclerViewAdapter.ViewHolder>(), Action1<ArrayList<Group>> {
最佳答案
view.adapter as GroupRecyclerViewAdapter
部分应该是 lambda func,而不是 Action,因为 onError 和 onComplete 也是 lambdas
所以,修复这个尝试:
.subscribe(
{ (view.adapter as GroupRecyclerViewAdapter).call(it) }
, { println(it.message) }
, { println("completed") }
)
用你的名字(用你的类型替换 Unit
)
class GroupRecyclerViewAdapter : Action1<Unit> {
override fun call(t: Unit?) {
print ("onNext")
}
}
使用 lambdas
val ga = GroupRecyclerViewAdapter()
...subscribe(
{ result -> ga.call(result) },
{ error -> print ("error $error") },
{ print ("completed") })
有 Action
...subscribe(
ga,
Action1{ error -> print ("error $error") },
Action0{ print ("completed") })
选择一个
关于Kotlin lambda 语法混淆,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34966999/