c - 分配内存后不执行代码

Question

在我为结构数组分配一些内存后，Compile 甚至不执行单个“printf”函数，为什么会发生这种情况？

int main(){
    setvbuf (stdout, NULL, _IONBF, 0);
    int entry_size;
    int all_ids [101] = {0};
    int studentSize;
    int max;
    student* Students = readStudents ("students1.txt", &entry_size, all_ids, &studentSize);
    printf ("%i \n", entry_size);
    int i;
    for (i = 1; i <= entry_size; i++){
        if(all_ids[i] != 0) studentSize++;
    }
    topThreeAvg *averages = malloc(studentSize * (sizeof(topThreeAvg)));
    for (i = 1; i <= entry_size; i++){
        printf("%s %s %i %i\n", (Students + i) -> firstName, (Students + i) -> secondName, (Students + i) -> ID, (Students + i) -> grade);
    }
    max = getMaxGrade (Students, entry_size);
    printf ("Max grade is %i \n", max); 
    fillAllStudentsAvgGrades (&averages, Students, entry_size, all_ids);
    return 0;
}

Answer 1

topThreeAvg *averages = malloc(studentSize * (sizeof(topThreeAvg)));
for (i = 1; i <= entry_size; i++){
    printf("%s %s %i %i\n", (Students + i) -> firstName, (Students + i) -> secondName, (Students + i) -> ID, (Students + i) -> grade);
}

您正在访问越界，请注意数组索引的范围是0...n-1，但您正在访问1...n。

因此将循环更改为如下所示，

for (i = 0; i < studentSize ; i++){

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旁注::另外

Students[i].ID

比

具有更好的可读性

(Students + i)->ID