我尝试了多种方法来执行bool is_tie函数中的代码;但是,我似乎总是在 check50 中收到相同的错误。
也就是说,我已经使用以下函数运行了该程序,使用最大候选人数(10 名选民),没有任何问题,并且有 7 名被淘汰的候选人或 2 名候选人,程序毫无问题地打印出 2 名并列候选人。我已经通过 debug50 运行了代码,在消除了另外两个候选人后,通过显示并列候选人的名字,它似乎可以正常工作;但是,在 check50 工具中,上述错误继续出现。
我还使用了 printf 函数来显示函数内的所有值,所有这些值似乎都是正确的。
我还在下面的 is_tie 函数中使用了 else {istie = false;} 我遇到了问题;但是,我收到了与错误下方的代码相同的错误。
**:( is_tie 在一些候选者被淘汰后检测到平局 - is_tie 没有返回 true **
bool is_tie(int min)
{
int ties = 0;
bool istie = false;
for (int i = 0; i < candidate_count; i++)
{
if (candidates[i].votes == min && candidates[i].eliminated == false)
{
ties++;
int elim_cands = candidate_count - candidates_out;
if (ties == candidate_count || ties == elim_cands)
{
istie = true;
break;
}
else
{
istie = false;
}
}
}
return istie;
}
同样,我已经能够使用下面的代码消除错误;但是,我只收到这两个错误。
:( 当选举不平局时 is_tie 返回 false
is_tie 没有返回 false
:( 当只有部分候选人并列时 is_tie 返回 false
is_tie 没有返回 false
bool is_tie(int min)
{
int ties = 0;
for (int i = 0; i < candidate_count; i++)
{
if (candidates[i].votes == min && candidates[i].eliminated == false)
{
ties++;
return true;
}
}
return false;
}
如果您有任何想法,请告诉我可以尝试什么。我一整天都在处理同样的错误,尽管该程序对我有用,但我无法提交带有错误的程序。我们将不胜感激您的想法。
所有其他功能都正常工作,问题集中的主要代码与最初提供的相同。我做到了;但是,添加一个名为candidates_out的全局变量来跟踪被淘汰的候选人的数量。
这是主要程序
#include <cs50.h>
#include <stdio.h>
#include <string.h>
// Max voters and candidates
#define MAX_VOTERS 100
#define MAX_CANDIDATES 9
// preferences[i][j] is jth preference for voter i
int preferences[MAX_VOTERS][MAX_CANDIDATES];
// Candidates have name, vote count, eliminated status
typedef struct
{
string name;
int votes;
bool eliminated;
}
candidate;
// Array of candidates
candidate candidates[MAX_CANDIDATES];
// Numbers of voters and candidates
int voter_count;
int candidate_count;
int candidates_out = 0;
// Function prototypes
bool vote(int voter, int rank, string name);
void tabulate(void);
bool print_winner(void);
int find_min(void);
bool is_tie(int min);
void eliminate(int min);
int main(int argc, string argv[])
{
// Check for invalid usage
if (argc < 2)
{
printf("Usage: runoff [candidate ...]\n");
return 1;
}
// Populate array of candidates
candidate_count = argc - 1;
if (candidate_count > MAX_CANDIDATES)
{
printf("Maximum number of candidates is %i\n", MAX_CANDIDATES);
return 2;
}
for (int i = 0; i < candidate_count; i++)
{
candidates[i].name = argv[i + 1];
candidates[i].votes = 0;
candidates[i].eliminated = false;
}
voter_count = get_int("Number of voters: ");
if (voter_count > MAX_VOTERS)
{
printf("Maximum number of voters is %i\n", MAX_VOTERS);
return 3;
}
// Keep querying for votes
for (int i = 0; i < voter_count; i++)
{
// Query for each rank
for (int j = 0; j < candidate_count; j++)
{
string name = get_string("Rank %i: ", j + 1);
// Record vote, unless it's invalid
if (!vote(i, j, name))
{
printf("Invalid vote.\n");
return 4;
}
}
printf("\n");
}
// Keep holding runoffs until winner exists
while (true)
{
// Calculate votes given remaining candidates
tabulate();
// Check if election has been won
bool won = print_winner();
if (won)
{
break;
}
// Eliminate last-place candidates
int min = find_min();
bool tie = is_tie(min);
// If tie, everyone wins
if (tie)
{
for (int i = 0; i < candidate_count; i++)
{
if (!candidates[i].eliminated)
{
printf("%s\n", candidates[i].name);
}
}
break;
}
// Eliminate anyone with minimum number of votes
eliminate(min);
// Reset vote counts back to zero
for (int i = 0; i < candidate_count; i++)
{
candidates[i].votes = 0;
}
}
return 0;
}
**SPOLER 警报 - 以下是与程序相关的功能代码:
bool vote(int voter,int order, string name) (void)tabulate(void) bool print_winner(void) bool is_tie(int min) int find_min(void) Elimination(int min)
bool vote(int voter, int rank, string name)
{
for (int number = 0; number < candidate_count; number++)
{
if (strcmp(name, candidates[number].name) == 0)
{
preferences[voter][rank] = number;
return true;
}
}
return false;
}
// Tabulate votes for non-eliminated candidates
void tabulate(void)
{
for (int j = 0; j < 1; j++) //loop to record each voters rank 1
{
for (int i = 0; i < voter_count; i++)
{
int number = preferences[i][j];
if (candidates[number].eliminated == false) //if candidate is not eliminated, add 1 to candidates votes
{
candidates[number].votes += 1;
j = 0;
}
else //if candidate is eliminated, go to the same voters next preference
{
i--;
j++;
}
}
}
}
// Print the winner of the election, if there is one
bool print_winner(void)
{
float majority = (float)voter_count / 2;
for (int i = 0; i < candidate_count; i++)
{
if (candidates[i].votes > majority)
{
printf("%s\n", candidates[i].name);
return true;
}
}
return false;
}
// Return the minimum number of votes any remaining candidate has
int find_min(void)
{
int min = candidates[0].votes;
for (int i = 1; i < candidate_count; i++)
{
if (min > candidates[i].votes && candidates[i].eliminated == false)
{
min = candidates[i].votes;
int Position = i;
}
}
return min;
}
// Eliminate the candidate (or candidiates) in last place
void eliminate(int min)
{
for (int i = 0; i < candidate_count; i++)
{
if (candidates[i].votes == min)
{
candidates[i].eliminated = true;
candidates_out++;
}
}
}
最佳答案
问题的根源:
add a global variable called candidates_out to keep track of the number of eliminated candidates.
来自the spec :
you should not modify anything else in
plurality.c
check50 使用它自己的黑魔法来运行测试并验证结果。 IMO 在本类(class)中学到的重要技能之一是严格遵循规范。在商业环境中,不这样做可能会转化为真正的金钱。
关于c - RUNOFF PSET3 - bool is_tie(int min) 函数在 Check50 中给出错误,无法删除,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59728647/