我正在用 C 语言编写 vector 加法代码。当我将参数传递为 1000 万时,我遇到了段错误。
我知道当我们访问进程地址空间之外的内存地址时会发生段错误。
但我不这么认为,这不是原因。
我的代码是:
#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>
struct timeval stop, start,start1,stop1;
void add(int a[], int b[],int N);
int main(int argc, char* argv[]){
gettimeofday(&start1, NULL);
if(argc<2){
printf("Please enter the value of N(number of elements)\n");
}else{
int i,N;
N=atoi(argv[1]);
N=N*1024;
int a[N],b[N];
for(i=0;i<=N;i++){
a[i]=rand()%1000;
b[i]=rand()%1000;
}
gettimeofday(&start, NULL);
add(a,b,N);
gettimeofday(&stop, NULL);
printf("took %lu us\n", (stop.tv_sec - start.tv_sec) * 1000000 + stop.tv_usec - start.tv_usec);
}
gettimeofday(&stop1, NULL);
printf("Total took %lu us\n", (stop1.tv_sec - start1.tv_sec) * 1000000 + stop1.tv_usec - start1.tv_usec);
return 0;
}
void add(int a[], int b[], int N){
int c,i;
for(i=0;i<=N;i++){
c=a[i]+b[i];
// printf("%d + %d = %d\n",a[i],b[i],c);
}
}
输出如下:(命令参数是数组的大小)
$ ./vectorAdd 1
took 9 us
Total took 233 us
$ ./vectorAdd 10
took 93 us
Total took 918 us
$ ./vectorAdd 100
took 210 us
Total took 4974 us
$ ./vectorAdd 1000
took 2371 us
Total took 20277 us
$ ./vectorAdd 10000
Segmentation fault (core dumped)
最佳答案
我试过了,它有效。感谢您的所有回复。这对我很有帮助。如果有任何优化请告诉我 输出:
$ ./vectorAdd 10000
took 34853 us
Total took 246023 us
#include<stdio.h>
#include<stdlib.h>
#include <sys/time.h>
struct timeval stop, start,start1,stop1;
void add(int *a, int *b, int *c, int N);
int *a, *b ,*c;
int main(int argc,char* argv[]){
gettimeofday(&start1, NULL);
if(argc<2){
printf("Please enter the value of N(number of elements)\n");
}
else
{
int i,N=0;
N=atoi(argv[1]);
N=N*1024;
a=(int *)malloc(N * sizeof(int));
b=(int *)malloc(N * sizeof(int));
c=(int *)malloc(N * sizeof(int));
for(i=0;i<N;i++){
a[i]=rand()%1000;
b[i]=rand()%1000;
}
gettimeofday(&start, NULL);
add(a,b,c,N);
gettimeofday(&stop, NULL);
printf("took %lu us\n", (stop.tv_sec - start.tv_sec) * 1000000 + stop.tv_usec - start.tv_usec);
free(a);
free(b);
free(c);
}
gettimeofday(&stop1, NULL);
printf("Total took %lu us\n", (stop1.tv_sec - start1.tv_sec) * 1000000 + stop1.tv_usec - start1.tv_usec);
return 0;
}
void add(int *a, int *b,int *c, int N){
int i;
for(i=0;i<=N;i++){
c[i]=a[i]+b[i];
// printf("%d + %d = %d\n",a[i],b[i],c[i]);
}
}
关于c - C中的执行时间差异,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60029740/