c - 访问结构体中定义的函数指针？

Question

编写一个程序，使用结构体structure2访问函数“foo”。

typedef struct
{
   int *a;
   char (*fptr)(char*);
}structure1;

typedef struct
{
   int x;
   structure1 *ptr;
}structure2;

char foo(char * c)
{
---
---
---
}

Answer 1

structure2 *s2 = (structure2*)malloc(sizeof(structure2));
s2->ptr = (structure1*)malloc(sizeof(structure1));
s2->ptr->fptr = foo;
char x = 'a';
s2->ptr->fptr(&x);