c 编程 : need fresh eyes to look at this [demo code ! = 作业]

Question

本质上我希望 qPtr[0] 保存 sPtr[0]

struct myQueue{  
    struct sample* node;  
    int front;  
    int size;  
    int numElements;  
};  

struct sample{  
    int field1[5];  
    char field2[10];  
}  

int main(){    
    struct myQueue* qPtr = malloc(10 * sizeof(struct myQueue);   
    struct sample* samplePtr = malloc(10 * sizeof(struct sample); //assume this array has                     been initialized    
    enqueue(qPtr, samplePtr[0]); //this does not work
}  

//returns 1 if enqueue was successful  
int enqueue(struct myQueue* qPtr, struct sample* sPtr){  

    qPtr->node[(qPtr->front + qPtr->numElements) % qPtr->size] = sPtr;  //code pertains to circular array implementation of queues  
    return 1;  
}  

我已经研究了大约 2 个小时，希望能对我在概念上做错了什么进行澄清。谢谢!

Answer 1

samplePtr[0] 给出对象本身，而不是指向对象的指针。尝试发送 &samplePtr[0] 或 samplePtr 本身。 enque 函数，第二个参数需要 struct example* 类型，而不是 struct example。