用于 atmega328p 的 USART 嵌入式 c。尝试在收到某个字符(在我的例子中为 char $)后存储用户输入的任何 10 个字符的数组。这可以为我编译,但仅当我使用 Hercules 实用程序阅读器输入一串字符时输出美元符号。感谢任何帮助
以下是我正在使用的代码的副本
#define FOSC 16000000 // Clock Speed
#define BAUD 9600
#define MYUBRR FOSC/16/BAUD-1
#include <avr/io.h>
//#include <stdio.h>
char trig='$';
char arr[10];
//This function is used to initialize the USART
//at a given UBRR value
void USARTInit(unsigned int ubrr)
{
//Set Baud rate
UBRR0H = (ubrr>>8);
UBRR0L = ubrr;
//Enable The receiver and transmitter
UCSR0B = (1<<RXEN0)|(1<<TXEN0);
// Set fram format: 8data 2stopBit
UCSR0C = (1<<USBS0)|(3<<UCSZ00);
}
//This function is used to read the available data
//from USART. This function will wait untill data is
//available.
unsigned char USARTReadChar( void )
{
//Wait untill a data is available
while(!(UCSR0A & (1<<RXC0)))
{
//Do nothing
}
//Now USART has got data from host
//and is available is buffer
return UDR0;
}
//This function writes the given "data" to
//the USART which then transmit it via TX line
void USARTWriteChar(unsigned char data)
{
//Wait untill the transmitter is ready
while(!(UCSR0A & (1<<UDRE0)))
{
//Do nothing
PORTD ^= 1 << PINB2;
}
//Now write the data to USART buffer
UDR0 = data;
}
int main(void)
{
DDRB |= 1 << PINB2;
//Varriable Declaration
char data;
USARTInit(MYUBRR);
//Loop forever
while(1)
{
//Read data
data = USARTReadChar();
int i =0;
//if incoming data is a dollar sign(trig),
if(data==trig)
{
//start a loop to collect data from buffer
for(i=0;i<10;i++)
{
//array has 10 elements, will fill up the ith element as per for loop
arr[i]=data;
// printf("arrayoutput %c\n",arr[i]);
USARTWriteChar(data);
}
}
}
}
我按照oleg的建议编辑了while循环,但仍然无法让它返回数组。整个代码如下:
#define FOSC 16000000 // Clock Speed
#define BAUD 9600
#define MYUBRR FOSC/16/BAUD-1
#include <avr/io.h>
#include <stdio.h>
char trig='$';
char arr[10];
//This function is used to initialize the USART
//at a given UBRR value
void USARTInit(unsigned int ubrr)
{
//Set Baud rate
UBRR0H = (ubrr>>8);
UBRR0L = ubrr;
//Enable The receiver and transmitter
UCSR0B = (1<<RXEN0)|(1<<TXEN0);
// Set fram format: 8data 2stopBit
UCSR0C = (1<<USBS0)|(3<<UCSZ00);
}
//This function is used to read the available data
//from USART. This function will wait untill data is
//available.
unsigned char USARTReadChar( void )
{
//Wait untill a data is available
while(!(UCSR0A & (1<<RXC0)))
{
//Do nothing
}
//Now USART has got data from host
//and is available is buffer
return UDR0;
}
//This function writes the given "data" to
//the USART which then transmit it via TX line
void USARTWriteChar(unsigned char data)
{
//Wait untill the transmitter is ready
while(!(UCSR0A & (1<<UDRE0)))
{
//Do nothing
PORTD ^= 1 << PINB2;
}
//Now write the data to USART buffer
UDR0 = data;
}
int main(void)
{
DDRB |= 1 << PINB2;
//Varriable Declaration
char data;
USARTInit(MYUBRR);
//Loop forever
//Read data
char input[10];
while(1){
data = USARTReadChar();
if(data == trig){
for(int i = 0; i < 10; i++){
//here we're saving 10 characters to input array
input[i] = USARTReadChar();
USARTWriteChar(input[i]);//tested without this also
}
}
}
}
最佳答案
尝试在 for() 循环中读取字符:
char input[10];
while(1){
data = USARTReadChar();
if(data == trig){
for(int i = 0; i < 10; i++){
//here we're saving 10 characters to input array
input[i] = USARTReadChar();
}
/* UPD: write stored array to console */
for(int i =0; i < 10; i++){
USARTWriteChar(input[i]);
}
/* those symbols are needed to emulate Enter button */
USARTWriteChar('\r');
USARTWriteChar('\n');
}
}
UPD:这段代码完全符合您的要求。它在内存中存储 10 个字符。要将它们返回到控制台(实用程序读取器),您必须使用 USARTWriteChar()。
关于c - USART嵌入C.触发字符存储数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19684606/