c - 使用结构实现一组，但出现错误

Question

它在 pushintoset 中给出错误数组未声明的函数首次在此函数中使用 '->' 的类型参数无效(具有 'int')

#include <stdio.h>
#include <stdlib.h>

struct set
{
    int data1;
    int data2;
    int size;
    int *array;
    int index;
};

struct set *createset(int capacity)
{
    struct set * s = (struct set*)malloc(sizeof(struct set));
     s->size = capacity;
     s->array = (int *)malloc(sizeof(int) * s->size);
    return s;
}

void pushintoset(struct set *st)       //giving error in this function that array undeclared                      
 {   
    int item1; 
    int item2;
    int i;
    for(i=0;i<5;i++)
    {
        printf("enter set %d \n",i);
        scanf("%d %d",&item1,&item2);
        st->index = i;
        st->array[st->index]->data1 = item1;
        st-array[st->index]->data2 = item2;
        st->array[st->index]->index = i;
    }
}

void printset(struct set * s)
{
    int i;
    for(i=1;i<=5;i++)
    {
        printf("%d  \t %d \n",s->array[i]->data1,s->array[i]->data2);
    }
}

int main()
{
    struct set * se = createset(5);
    if(se==NULL)``
    printf("memory not allocate");
    pushintoset(se);
    printset(se);
    return 0;
}

Answer 1

st-array[st->index]->data2 = item2; // loss of '>' after 'st-'

并且您不应该在此处将结构成员数组作为结构点进行访问。