这是我的作业:
创建一个程序,允许用户输入最多 10 个 friend 的地址。使用二维数组来存储 friend 的地址。输入每个地址后,用户应该可以选择输入另一个地址或打印一份报告,显示迄今为止输入的每个地址。
我明白了大部分内容,但我遇到了 fgets 的主要问题。我不断收到此错误:
warning: passing arg 1 of `fgets' makes pointer from integer without a cast
代码:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main ()
{
char name[20]= {0};
char address[40]= {100};
int choice;
int i;
printf("Welcome to the Address Book!\n\n");
for (i=0;i<10;i++) //start of the array loop. should give an exit after each entry
{
printf("Would you like to (1)Enter an address, or (2)Print the address book?\n");
scanf("%i",&choice);
switch (choice)
{
case 1:
{
printf("Please enter a name...\n");
fgets(name[i],20,stdin);
printf("You entered %s .", name);
printf("Please enter an address...\n");
fgets(address[i],40,stdin);
printf("You enteres %s .", address);
}
break;
case 2:
for (i = 0; i<10; i ++)
{
printf("%s\n", name[i]);
printf("%s\n", address[i]);
}
break;
}
}
return (0);
}
最佳答案
在下面找到更正的代码
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main ()
{
char name[10][20]; //Fix3
char address[10][40];//Fix4
int choice;
int i, j;
printf("Welcome to the Address Book!\n\n");
for (i=0;i<10;i++) //start of the array loop. should give an exit after each entry
{
printf("Would you like to (1)Enter an address, or (2)Print the address book?\n");
scanf("%i",&choice);
switch (choice)
{
case 1:
{
printf("Please enter a name...\n");
getchar(); //Fix1
fgets(name[i],20,stdin);
printf("You entered %s .", name);
printf("Please enter an address...\n");
//getchar();//Fix2
fgets(address[i],40,stdin);
printf("You enteres %s .", address);
}
break;
case 2:
{
for (j = 0; j<i; j ++)
{
printf("%s\n", name[j]);
printf("%s\n", address[j]);
}
}
break;
}
}
return (0);
}
更正如下:
- 二维数组用于获取姓名和地址
- 在使用fgets()之前调用getchar()来消耗'\n';
关于c - 二维数组地址簿存在 fgets 问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25093210/