将 char 数组转换为 hex 数组

Question

输入:

char arr1[9] = "+100-200"  // (+ is 2B, - is 2D, 1 is 31 and 2 is 32)

输出:

unsigned int arr2[4]= [0x2B31,0x3030,0x2D32,0x3030]

我该怎么做？

Answer 1

您的问题似乎不一致:0 应该转换为 0x30，它的 ASCII 值。

为什么要这样修改，代码很简单:

char arr1[8] = "+100-200";
unsigned int arr2[4];

for (int i = 0; i < 8; i += 2) {
    arr2[i / 2] = ((unsigned int)(unsigned char)arr1[i] << 8) |
                   (unsigned int)(unsigned char)arr1[i + 1];
}

for (int i = 0; i < 4; i++) {
    printf("0x%04X ", arr2[i]);
}
printf("\n");

输出:

0x2B31 0x3030 0x2D32 0x3030