c - 为什么我收到聚集初始化程序不是编译时常量警告？

Question

我有这样的结构

struct set
{
    char name[SET_NAME_LENGTH + 1];
    unsigned int input[INPUT_ARR_SIZE];
};

typedef struct set SETA, SETB, SETC, SETD, SETE, SETF;

然后我有这样的代码

SETA setA;
SETB setB;
SETC setC;
SETD setD;
SETE setE;
SETF setF;

struct set * p_setA = &setA;
struct set * p_setB = &setB;
struct set * p_setC = &setC;
struct set * p_setD = &setD;
struct set * p_setE = &setE;
struct set * p_setF = &setF;

int main()
{ 
    int resultStatus, r;
    int num_of_sets = 6;
    int i;
    int input_method = NOT_CHOOSEN_INPUT;

    struct set * struct_arr[] = {
        p_setA,
        p_setB,
        p_setC,
        p_setD,
        p_setE,
        p_setF
    };

    memcpy(p_setA->name, SETA_NAME, sizeof(SETA_NAME));
    memcpy(p_setB->name, SETB_NAME, sizeof(SETB_NAME));
    memcpy(p_setC->name, SETC_NAME, sizeof(SETC_NAME));
    memcpy(p_setD->name, SETD_NAME, sizeof(SETD_NAME));
    memcpy(p_setE->name, SETE_NAME, sizeof(SETE_NAME));
    memcpy(p_setF->name, SETF_NAME, sizeof(SETF_NAME));

    for(i = 0; i < num_of_sets; i++)
    {
        printf("\nSET NAME IS : %s\n", struct_arr[i]->name);
    }
...
}

但是日志输出不符合我的预期

SET NAME IS : SETA

SET NAME IS : SETA

SET NAME IS : SETA

SET NAME IS : SETA

SET NAME IS : SETA

SET NAME IS : SETA

还有警告

warning: initializer for aggregate is not a compile-time constant

警告

如何解决？

Answer 1

当程序执行时，变量setA会被放置在内存中的某个地方，但编译器不知道在哪里。它的地址，在p_setA中，不是编译时常量，并且不能用作C中的初始化器。只需使用正常赋值而不是初始化。