我正在学习 Swift，我在 DesignCode 上开设类(class)，现在我正在尝试创建一个应用程序来改进我所学的知识。
这就是我所做的:
我创建了 UIViewController 并执行到 UITableViewController 的 segue；
在 UITableViewController 中，我嵌入了导航栏，在其中创建了“后退”栏按钮项；
我将此“返回”链接到退出，通过“Spring”执行转场以放松。
当我单击此按钮时，我收到以下错误:
2015-06-04 15:32:08.662 Vitrine[2883:67901] *** Assertion failure in -[UIStoryboardUnwindSegueTemplate _perform:], /SourceCache/UIKit_Sim/UIKit-3347.44/UIStoryboardUnwindSegueTemplate.m:78
2015-06-04 15:32:08.676 Vitrine[2883:67901] *** Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'Could not find a view controller to execute unwinding for <UINavigationController: 0x7ae41540>'
*** First throw call stack:
(
0 CoreFoundation 0x0154d746 __exceptionPreprocess + 182
1 libobjc.A.dylib 0x02f4ea97 objc_exception_throw + 44
2 CoreFoundation 0x0154d5da +[NSException raise:format:arguments:] + 138
3 Foundation 0x019c3720 -[NSAssertionHandler handleFailureInMethod:object:file:lineNumber:description:] + 118
4 UIKit 0x0253d3b4 -[UIStoryboardUnwindSegueTemplate _perform:] + 387
5 UIKit 0x0237c313 -[UIStoryboardSegueTemplate perform:] + 116
6 libobjc.A.dylib 0x02f647cd -[NSObject performSelector:withObject:withObject:] + 84
7 UIKit 0x01d72a90 -[UIApplication sendAction:to:from:forEvent:] + 99
8 UIKit 0x020f8bba -[UIBarButtonItem(UIInternal) _sendAction:withEvent:] + 139
9 libobjc.A.dylib 0x02f647cd -[NSObject performSelector:withObject:withObject:] + 84
10 UIKit 0x01d72a90 -[UIApplication sendAction:to:from:forEvent:] + 99
11 UIKit 0x01d72a22 -[UIApplication sendAction:toTarget:fromSender:forEvent:] + 64
12 UIKit 0x01eb318a -[UIControl sendAction:to:forEvent:] + 69
13 UIKit 0x01eb35a7 -[UIControl _sendActionsForEvents:withEvent:] + 598
14 UIKit 0x01eb2811 -[UIControl touchesEnded:withEvent:] + 660
15 UIKit 0x01dcacfa -[UIWindow _sendTouchesForEvent:] + 874
16 UIKit 0x01dcb7d6 -[UIWindow sendEvent:] + 792
17 UIKit 0x01d896d1 -[UIApplication sendEvent:] + 242
18 UIKit 0x01d99b08 _UIApplicationHandleEventFromQueueEvent + 21484
19 UIKit 0x01d6d337 _UIApplicationHandleEventQueue + 2300
20 CoreFoundation 0x0146f06f __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 15
21 CoreFoundation 0x01464b7d __CFRunLoopDoSources0 + 253
22 CoreFoundation 0x014640d8 __CFRunLoopRun + 952
23 CoreFoundation 0x01463a5b CFRunLoopRunSpecific + 443
24 CoreFoundation 0x0146388b CFRunLoopRunInMode + 123
25 GraphicsServices 0x050c62c9 GSEventRunModal + 192
26 GraphicsServices 0x050c6106 GSEventRun + 104
27 UIKit 0x01d71106 UIApplicationMain + 1526
28 Vitrine 0x00076cd4 main + 180
29 libdyld.dylib 0x0366bac9 start + 1
)
libc++abi.dylib: terminating with uncaught exception of type NSException
问候， 迪奥戈·阿马拉尔
最佳答案
您必须在想要返回的 View 中创建一个如下所示的 IBAction:
@IBAction func back(segue:UIStoryboardSegue) {
//no code here, unless you want to do something when exiting
}
然后，在您想要退出的 View 中，将您的 barButtonItem 链接到退出(IBAction 应该出现在那里)。
关于ios - 放松不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30651602/