这是我的代码:
var usernames = [""]
var userids = [""]
var isFollowing = ["":false]
var refresher: UIRefreshControl!
func refresh() {
var query = PFUser.query()
query?.findObjectsInBackgroundWithBlock({ (objects, error) -> Void in
if let users = objects {
self.usernames.removeAll(keepCapacity: true)
self.userids.removeAll(keepCapacity: true)
self.isFollowing.removeAll(keepCapacity: true)
for object in users {
if let user = object as? PFUser {
if user.objectId != PFUser.currentUser()!.objectId {
self.usernames.append(user.username!)
self.userids.append(user.objectId!)
var query = PFQuery(className: "followers")
query.whereKey("follower", equalTo: PFUser.currentUser()!.objectId!)
query.whereKey("following", equalTo: user.objectId!)
query.findObjectsInBackgroundWithBlock({ (objects, error) -> Void in
if let objects = objects {
if objects.count > 0 {
self.isFollowing[user.objectId!] = true
} else {
self.isFollowing[user.objectId!] = false
}
}
if self.isFollowing.count == self.usernames.count {
self.tableView.reloadData()
self.refresher.endRefreshing()
}
})
}
}
}
}
})
我在这行收到 fatal error ，内容如下:
query.whereKey("follower", equalTo: PFUser.currentUser()!.objectId!) query.whereKey("following", equalTo: user.objectId!)
我该如何解决这个问题？我搜索了其他几个帖子，但找不到有用的东西。当您提供建议时，请非常具体——我相对来说是一个新手。
最佳答案
正如评论中所说，您的值(value)观之一是零。
在查询之前插入以下代码并修复返回 nil 的方法:
if (PFUser.currentUser() == nil) {
print("currentUser() is nil");
} else if (PFUser.currentUser()!.objectId == nil) {
print("PFUser.currentUser()!.objectId is nil");
} else if (user.objectId == nil) {
print("user.objectId is nil");
}
关于ios - 为什么我会收到以下错误 : "fatal error: unexpectedly found nil while unwrapping an Optional value"? - 如何具体修复它？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33127050/