我想要一个 API key 并验证用户身份。我在控制台中看到消息“ session URL 任务成功:HTTP 200”。不幸的是,我总是收到页面“{”消息“:”的消息。此请求“}”的授权已被拒绝。我花了几个小时寻找并找到了解决方案。我请求你的帮助。这是我的代码:
let sessionConfig = NSURLSessionConfiguration.defaultSessionConfiguration()
let session = NSURLSession(configuration: sessionConfig, delegate: nil, delegateQueue: nil)
let URL = NSURL(string: "https://api.testhomepage.com/api/contact")
let request = NSMutableURLRequest(URL: URL!)
// Headers
request.addValue("ARRAffinity=259dfjiehfs315d7249df8805c7895a98c4cbd3327ffdcb82aaa16317f2e6", forHTTPHeaderField: "Cookie")
request.addValue("Basic dWVzQGp1bGl0ZafdgfvcfgeDcyZS1hZWEyLTQzYmVmMjFhNDMxZQ==", forHTTPHeaderField: "Authorization")
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("api.testhomepage.com", forHTTPHeaderField: "Host")
request.addValue("//api.testhomepage.com/api/contact: POST", forHTTPHeaderField: "https")
request.HTTPMethod = "GET"
// JSON Body
/* Start a new Task */
let task = session.dataTaskWithRequest(request) { (data: NSData?, response: NSURLResponse?, error: NSError?) -> Void in
if (error == nil) {
// Success
let statusCode = (response as! NSHTTPURLResponse).statusCode
print("URL Session Task Succeeded: HTTP \(statusCode)")
let myURLString = "https://api.testhomepage.com/api/contact"
if let myURL = NSURL(string: myURLString) {
var error: NSError?
let myhtml = try! NSString(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)
if let error = error {
print("Error : \(error)")
} else {
print("HTML : \(myhtml)")
}
} else {
print("Error: \(myURLString) doesn't seem to be a valid URL")
}
}
else {
// Failure
print("URL Session Task Failed: %@", error!.localizedDescription);
}
}
task.resume()
}
这是在控制台中:
URL session 任务成功:HTTP 200 HTML : {"Message":"此请求的授权已被拒绝。"}
最佳答案
使用 request.setvalue("", forHTTPHeaderField: "")
而不是 request.addValue("", forHTTPHeaderField: "")
关于swift - NSURLSession:无需身份验证即可 NSURLSession ( Swift ),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33966263/