我在调用 tweet 函数时遇到问题。我不断收到参数错误。我也尝试了 (AnyObject) 并得到了 错误:参数类型不符合预期...
我是 swift 新手,不知道如何运行它。尝试了我能想到的一切。谢谢
// from GameScene
var vc = ViewController()
vc.tweetAction(sender: AnyObject)
//error: cannot create single-element tuple with an element label
//function in View Controller below
@IBAction func tweetAction(sender: AnyObject){
if SLComposeViewController.isAvailableForServiceType(SLServiceTypeTwitter){
let tweetController = SLComposeViewController(forServiceType: SLServiceTypeTwitter)
tweetController.setInitialText("I Scored on this app")
self.presentViewController(tweetController, animated: true, completion: nil)
}
else{
let alert = UIAlertController(title: "Accounts", message: "Please log into your twitter to share", preferredStyle: UIAlertControllerStyle.Alert)
alert.addAction(UIAlertAction(title: "Dismiss", style: UIAlertActionStyle.Default, handler: nil))
alert.addAction(UIAlertAction(title: "Settings", style: UIAlertActionStyle.Default, handler: { (UIAlertACtion) in
let settingsURL = NSURL(string:UIApplicationOpenSettingsURLString)
if let url = settingsURL{
UIApplication.sharedApplication().openURL(url)
}
}))
self.presentViewController(alert, animated: true, completion: nil)
}
}
最佳答案
您正在向方法调用传递类型而不是实例。您还包括第一个参数的标签,这是不正确的。尝试:
vc.tweetAction(self)
关于swift - 从 View Controller 调用函数 - 参数错误 - Swift2,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37823140/