在 swift 2.2 中它的工作原理:
var messages = [JSQMessage]()
//...
for i in 1...10 {
let sender = (i%2 == 0) ? "Server" : self.senderId
let messageContent = "Message nr. \(i)"
var message = JSQMessage(senderId: sender, displayName: sender, text: messageContent)
self.messages += [message] //Cannot convert value of type '[JSQMessage]' to expected argument type 'inout_'
}
在 swift 3 中给我错误。尝试使用
self.messages += [&message] // Type of expression is ambiguous without more context
如何解决?
最佳答案
关于swift 3 更新 swift 2 的语法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40194552/