ios - 将 Swift 3.0 的选择器转换为 2.2

Question

let selector: Selector = #selector(getter: UIPrinter.displayName)

我想将此行转换为 swift 2.2

这是函数的完整代码

func indexFiles() {

       let selector: Selector = #selector(getter: UIPrinter.displayName)
        sections = Array(repeating: [], count: collation.sectionTitles.count)



        if let sortedObjects = collation.sortedArrayFromArray(files, collationStringSelector: selector) as? [FBFile]{
            for object in sortedObjects {
                let sectionNumber = collation.sectionForObject(object, collationStringSelector: selector)
                sections[sectionNumber].append(object)
            }
        }
    }

Answer 1

尝试从 UIPrinter 实例变量获取选择器。您可以使用

Selector 类的 public init(_ str: String) 初始值设定项。

    let url = NSURL(fileURLWithPath: "file url ")
    let printer = UIPrinter(URL:url)
    let selector:Selector = Selector(printer.displayName)