arrays - Swift:对字典数组中的键值对进行排序

Question

我必须为我的第一个项目(在线类(class))对字典数组进行排序。排序尚未被涵盖，我只能自己做一些研究。确实去了Apple并阅读了有关闭包的内容，观看了youtube以了解排序的概念，但我仍然对如何设置逻辑感到有点困惑(我假设是func)

这是我目前收藏的作品

var players: [[String: Any]] = [

        ["Name": "Joe Smith",
        "Height": 42,
        "Experience": true,
        "Guardians": "Jime and Jan Smith",
        "Team": ""],

        ["Name": "Jill Tanner",
        "Height": 36,
        "Experience": true,
        "Guardians": "Clara Tanner",
        "Team": ""],

        ["Name": "Bill Bon",
        "Height": 43,
        "Experience": true,
        "Guardians": "Sara and Jenny Bon",
        "Team": ""],
]

任何提示或来源都会非常感谢!

Answer 1

我强烈建议您将数据转换为结构数组(或者可能是对象)，而不是字典数组。使用 Dictionary 所需的弱类型(即使用 Any 作为值的类型)使得字典使用起来非常烦人。此外，使用词典时还会对性能和安全性造成巨大影响。

struct Player {
    let name: String
    let height: Int
    let experience: Bool
    let guardians: String
    let team: String?
}

let players = [
    Player(
        name: "Joe Smith",
        height: 42,
        experience: true,
        guardians: "Jime and Jan Smith",
        team: nil
    ),
    Player(
        name: "Jill Tanner",
        height: 36,
        experience: true,
        guardians: "Clara Tanner",
        team: nil
    ),
    Player(
        name: "Bill Bon",
        height: 43,
        experience: true,
        guardians: "Sara and Jenny Bon",
        team: nil
    ),
]

// Example, sort by height

let sortedPlayers = players.sorted{ $0.height < $1.height }

for player in sortedPlayers {
    print(player)
}

我为 Array 的 sorted 方法提供了一个闭包，告诉它如何在任意两个给定元素之间执行比较。在此示例中，我编写了一个闭包，将矮个玩家放在高个玩家之前。