流程是: 1 用户使用touch id登录 2. 用户注销(logout Dismiss to Login) 然后应用程序自动触发触摸 ID 并成功响应(这不会在模拟器中发生)帮助!!
这是我在登录 View Controller 上的监听器
override func viewWillAppear(_ animated: Bool) {
super.viewWillAppear(animated)
if authenticationContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) && DataContainerSingleton.sharedDataContainer.fingerPrintEnabled == "SI"{
self.touchIdListener()
}
}
与
func touchIdListener(){
authenticationContext.evaluatePolicy(
.deviceOwnerAuthenticationWithBiometrics,
localizedReason: self.valFromCurrentLanguaje(valor: "LOGIN_FINGER_MSG"),
reply: { [unowned self] (success, error) -> Void in
if( success ) {
let keychain = KeychainSwift()
let data = keychain.get(Constants.USER_KEY)?.components(separatedBy: ",")
DispatchQueue.main.async {
self.showProgress(text: Constants.EMPTY_STRING)
}
self.fromTouchId = true
self.loginBL.startLogin(email: (data?[0])!, password: data?[1])
}else {
// Check if there is an error
if let error = error {
print("\(error.localizedDescription)")
}
}
})
}
最佳答案
所以解决方案是更改解雇
self.dismiss(animated: true, completion: nil)
对于新实例
var storyboard = UIStoryboard()
let vc : LoginViewController
if (Constants.IS_IPAD) {
storyboard = UIStoryboard.init(name: "LoginIpad", bundle: nil)
vc = storyboard.instantiateViewController(withIdentifier: "ipadViewController") as! LoginViewController
} else {
storyboard = UIStoryboard.init(name: "Login", bundle: nil)
vc = storyboard.instantiateViewController(withIdentifier: "iphoneViewController") as! LoginViewController
}
let navigationController = UINavigationController(rootViewController: vc)
self.present(navigationController, animated: true, completion: nil)
关于ios - 当我从另一个 View 中退出时,Touch ID 自动触发成功,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45086336/