ios - 排除 HandyJSON 中的属性

Question

我正在使用 HandyJSOn 框架来序列化和反序列化 Swift3 中的对象。现在我遇到的问题是我想从这个过程中排除一些属性。我尝试按照 GitHub 页面上给出的步骤进行操作，但无法开始工作:

class MyClass : HandyJSON {
  private var excludeThisProperty : String

  public func mapping(mapper: HelpingMapper) {
    mapper >>> self.excludeThisProperty
  }
}

编译器失败并出现错误:

binary operator >>> cannot be applied to operands of type HelpingMapper and String

+++ 示例+++

class MyClass : HandyJSON {
    private let myPropertyDefault : String? = "example"
    private var myProperty : String

    public required init() {
        myProperty = myPropertyDefault!
    }

    public func reset() {
        myProperty = myPropertyDefault!
    }

    public func mapping(mapper: HelpingMapper) {
        mapper >>> self.myPropertyDefault
    }
}

Answer 1

请将您的字符串更改为可选:

private var excludeThisProperty : String?

示例代码:

let jsonString = "{\"excludeThisProperty\":\"sdfsdf\"}"

if let myclass = MyClass.deserialize(from: jsonString) {
    print(myclass)
}

class MyClass : HandyJSON {
    private var myPropertyDefault : String? = "example" // changed from let to var
    private var myProperty : String

    public required init() {
        myProperty = myPropertyDefault!
    }

    public func reset() {
        myProperty = myPropertyDefault!
    }

    public func mapping(mapper: HelpingMapper) {
        mapper >>> self.myPropertyDefault
    }
}