这是swift 4代码:
protocol BarProtocol {
associatedtype Bar
var bar:Bar? {get set}
}
class FooClass : BarProtocol {
//typealias Bar = (String) -> ()
typealias Bar = (String)
var bar: Bar?
}
func configFooClass<T:BarProtocol>(fooClass:inout T, bar:T.Bar) {
fooClass.bar = bar
}
func setupFooClass(fooClass:inout FooClass, bar:FooClass.Bar) {
configFooClass(fooClass: &fooClass, bar: bar)
}
var fooClass = FooClass()
var barString = "barString"
//let barAction:(String) -> () = { text in
// print(text)
//}
setupFooClass(fooClass:&fooClass, bar:barString)
print(fooClass.bar) // print: Optional("barString")
到目前为止一切顺利,它将在控制台中打印“Optional("barString")”。 FooClass类中的关联类型现在是String类型,因此它可以存储字符串值“barString”。
但是如果我将此代码更改为:
protocol BarProtocol {
associatedtype Bar
var bar:Bar? {get set}
}
class FooClass : BarProtocol {
typealias Bar = (String) -> ()
// typealias Bar = (String)
var bar: Bar?
}
func configFooClass<T:BarProtocol>(fooClass:inout T, bar:T.Bar) {
fooClass.bar = bar
}
func setupFooClass(fooClass:inout FooClass, bar:FooClass.Bar) {
configFooClass(fooClass: &fooClass, bar: bar)
// Error here: Cannot convert value of type '(String) -> ()' to expected argument type '_.Bar'
}
var fooClass = FooClass()
var barString = "barString"
let barAction:(String) -> () = { text in
print(text)
}
//setupFooClass(fooClass:&fooClass, bar:barString)
//print(fooClass.bar)
setupFooClass(fooClass:&fooClass, bar:barAction)
fooClass.bar!("lalalalala")
实际上,我只是将 FooClass 的关联类型从 String 更改为 (String) -> (),就会出现错误: Cannot conversion value of type '(String) -> ()' to Expected argument type '_.Bar '
我不明白,似乎闭包可以作为函数的参数传递。但为什么 'String' 类型工作得很好,而 '(String) -> ()' 却不行?
最佳答案
看来添加@escaping可以解决这个问题...
func setupFooClass(fooClass:inout FooClass, bar:@escaping FooClass.Bar) {
configFooClass(fooClass: &fooClass, bar: bar)
}
关于swift - 当类型是关联类型时,无法将类型的值转换为预期的参数类型,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48658969/