快速解析 desc 并解析所选元素。我想解析 desc 并在解析 desc 后解析 desc 内容。感谢快速解析 desc 和解析所选元素。
我尝试过不同的方法。有谁知道我们如何才能实现这一目标？我尝试了以下代码:
**Code for getting the data**
func demoApi1() {
Alamofire.request("", method: .get, parameters: nil, encoding: JSONEncoding.default, headers: nil).responseJSON { (response:DataResponse<Any>) in
switch(response.result) {
case .success(_):
guard let json = response.result.value as! [[String:Any]]? else{ return}
print("Ang Response: , \(json)")
for item in json {
self.getAllDetail.append(item )
if let desc = item["dec"] as? String {
self.titleArray.append(desc)
print("motherfucker:" , self.titleArray)
}
}
if !self.getAllDetail.isEmpty{
DispatchQueue.main.async {
}
}
break
case .failure(_):
print("Error")
break
}
}
}
回应:
Ang Response [["status": {
name = ongoing;
}, "sched": 2018-04-10T14:22:00+08:00, "desc": asdasdasdsa, "id": 224, "reward": 1.00, "parent": das, "child": dasdas, "date_created": 2018-04-19T15:54:24.657644+08:00, "name": sad, "occurrence": {
name = once;
}, "type": , "date_modified": 2018-04-19T15:54:24.703520+08:00], ["status": {
name = ongoing;
}, "sched": 2018-04-19T15:54:24.657644+08:00, "desc": {
"questions" : [
{
"b" : 2,
"a" : 1
},
{
"b" : 3,
"a" : 2
},
{
"b" : 2,
"a" : 8
},
{
"b" : 9,
"a" : 7
},
{
"b" : 3,
"a" : 6
}
],
"operation" : "addition"
}, "id": 226, "reward": 1.00, "parent": shit, "child": , "date_created": 2018-04-23T14:16:35.739436+08:00, "name": chorename, "occurrence": {
name = once;
}, "type": homework, "date_modified": 2018-04-23T14:16:35.790237+08:00]]
最佳答案
字符串到字典:
func stringToDictionary(_ strToJSON : String)-> [String:Any]{
print("JsonString:\(strToJSON)")
let data = strToJSON.data(using: .utf8)
var dict = [String:Any]()
do {
dict = try JSONSerialization.jsonObject(with: data!) as! [String:Any]
return dict
}
catch let error as NSError {
print("Error is:\(error)")
}
return dict
}
像这样使用它:
let dictConv = stringToDictionary("your_string")
print(dictConv)
关于ios - 快速解析 desc 并解析所选元素，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/49977962/