ios - 未在物理设备上获取联系人 - iOS

Question

我目前正在尝试使用 TestFlight 测试我的 iOS 应用程序，但在获取联系人时遇到了一些问题。我的应用程序应该检索通讯录中的所有联系人，然后在检查 firebase 以确保联系人尚未被邀请到应用程序后将它们显示在表格 View 中。它在有 10 个联系人的模拟器上工作正常，但在我有 100 多个联系人的手机上根本不起作用。甚至没有出现任何联系方式。我检查过我是否也启用了联系人。不确定可能是什么问题。我已附上以下代码:

override func viewDidLoad() {
    super.viewDidLoad()

    contactStore.requestAccess(for: .contacts) { (success, error) in
        if success{
            print("Contact Authorization Successful")
        }
    }
    fetchContacts()
    tableView.delegate = self
    tableView.dataSource = self
}
func fetchContacts(){
    contacts = [ContactStruct]()
    let key = [CNContactGivenNameKey, CNContactFamilyNameKey, CNContactPhoneNumbersKey, CNContactImageDataKey, CNContactThumbnailImageDataKey] as [CNKeyDescriptor]
    let request = CNContactFetchRequest(keysToFetch: key)
    try! contactStore.enumerateContacts(with: request) { (contact, stoppingPointer) in
        let name = contact.givenName
        let familyName = contact.familyName
        let fullName = contact.givenName + contact.familyName
        let number = (contact.phoneNumbers[0].value ).value(forKey: "digits") as! String
        let contactImage = contact.imageData


        let phone = (contact.phoneNumbers[0].value ).value(forKey: "digits") as! String

            self.phoneNumbersArray.append(phone)


        let contactToAppend = ContactStruct(givenName: name, familyName: familyName, fullName: fullName, phoneNumber: number, contactImage: contactImage)

        self.contacts.append(contactToAppend)
        self.tableView.reloadData()
    }
    getAllUsers()
}


func getAllUsers(){
    self.sectionData = [0: self.contactsOnApp as Array<AnyObject>, 1: self.usersInSchool as Array<AnyObject>, 2: self.contacts as Array<AnyObject>]
    ref.child("users").child(uid!).observeSingleEvent(of: .value, with: { (snapshot) in
        let user = User(snapshot: snapshot)
        let currentUserSchool = user.highSchool!

        for child in user.invitesFormatted {
            let checkInvites = child
                if let alreadyInvited = self.contacts.index(where: {$0.phoneNumber == checkInvites}){
                    self.contacts.remove(at: alreadyInvited)
                    self.sectionData = [0: self.contactsOnApp as Array<AnyObject>, 1: self.usersInSchool as Array<AnyObject>, 2: self.contacts as Array<AnyObject>]
                    self.tableView.reloadData()
                }
        }

        ref.child("schools").child(currentUserSchool).child("members").observeSingleEvent(of: .value, with: { (snap) in

            for child in snap.children{

                let child = child as? DataSnapshot
                if let otherUsers = child?.key {
                    ref.child("users").child(otherUsers).observeSingleEvent(of: .value, with: { (snappy) in
                        let personInSchool = User(snapshot: snappy)

                        if personInSchool.uid != uid! && self.phoneNumbersArray.contains(personInSchool.phoneNumber) {
                            //If contacts does have user
                            self.contactsOnApp.append(personInSchool)

                                if let itemToRemoveIndex = self.contacts.index(where: {$0.phoneNumber == personInSchool.phoneNumber}) {
                                        self.contacts.remove(at: itemToRemoveIndex)
                            }   
                        }else if personInSchool.uid != uid! {
                            //If contacts doesn't have user
                            self.usersInSchool.append(personInSchool)   
                        }
                        self.sectionData = [0: self.contactsOnApp as Array<AnyObject>, 1: self.usersInSchool as Array<AnyObject>, 2: self.contacts as Array<AnyObject>]
                        self.tableView.reloadData()
                    })
                }
            }
        })
    })
}

任何帮助将不胜感激。谢谢!

Answer 1

仅当设备已授予应用访问权限时，您才能获取联系人。我的猜测是您没有授予应用程序访问权限，因此您的 fetchContacts() 将永远无法工作。

在真实设备上全新安装该应用。如果您请求正确使用用户联系人的权限，那么这应该会触发应用程序询问使用情况。确保在弹出消息上单击"is"。您还可以检查“设置”应用程序下的“应用程序设置”，然后重新启用该应用程序以允许访问联系人。