swift - 将 UI 与逻辑 Swift 连接时出现关闭错误

Question

我需要将 UI 与模块连接起来。

错误:无法将类型“()”的值转换为闭包结果类型“Bool”

Controller 代码:

private func connectLogicView() {
    screenView.handlePlayPauseButton(sender: screenView.playPauseButton) { () -> Bool in

        obj.playPause(queue: .global()) { //Error here
            if self.obj.getPlayer().timeControlStatus != .paused {
                return true
            } else if self.obj.getPlayer().timeControlStatus == .paused {
                return false
            }
        }
    }
}

模块代码:

public func playPause(queue: DispatchQueue, completion: @escaping ()->Void){
    if player.timeControlStatus == .playing {
        player.pause()
    } else {
        player.play()
    }
    queue.async {
        completion()
    }
}

用户界面代码:

func handlePlayPauseButton(sender: UIButton, completion: () -> Bool) {
    if completion() == true {
        sender.setTitle("pause", for: .normal)
    } else {
        sender.setTitle("play", for: .normal)
    }
}

如果您能提供更好的方法，我们将不胜感激。

Answer 1

playPause 方法在 completion block 中没有任何内容，但是

 obj.playPause(queue: .global()) { 
        if self.obj.getPlayer().timeControlStatus != .paused {
            return true // NO NEED FOR THIS LINE
        } else if self.obj.getPlayer().timeControlStatus == .paused {
            return false  // NO NEED FOR THIS LINE
        }
   }

您返回 true 或 false 删除它，您的代码将正常运行