我正在尝试使用 Alamofire
从 URL 获取 JSON
下载。
Alamofire.request(requrl, method: .get, encoding: JSONEncoding.default)
.responseJSON { response in
print(response.result)
print(response.value)
debugPrint(response)
}
但是response.value
的值为nil,请求结果状态为FAILURE。日志中包含以下内容:
>[Data]: 919 bytes
[Result]: FAILURE: responseSerializationFailed(Alamofire.AFError.ResponseSerializationFailureReason.jsonSerializationFailed(Error Domain=NSCocoaErrorDomain Code=3840 "Invalid value around character 0." UserInfo={NSDebugDescription=Invalid value around character 0.}))
[Timeline]: Timeline: { "Request Start Time": 561988246.258, "Initial Response Time": 561988246.446, "Request Completed Time": 561988246.447, "Serialization Completed Time": 561988246.447, "Latency": 0.189 secs, "Request Duration": 0.189 secs, "Serialization Duration": 0.000 secs, "Total Duration": 0.190 secs
php 脚本
<?php
header('Content-type: application/json');
//header('Content-Type: html; charset=utf-8');
$sqlstatement = $_GET["sqlstatement"];
// Create connection
$dbConnection=mysqli_connect("***.***.gear.host","****","*****!","****");
//$sqlstatement = "SELECT * FROM reeds.tbl_user";
// Check connection
if (mysqli_connect_errno())
{
// Print error message
echo mysqli_connect_error();
}
// Stores SQL statement, selecting all objects from testcomputing.name
// Check to ensure results > = 1
if ($result = mysqli_query($dbConnection, $sqlstatement))
{
// If so, then create a results array and a temporary one to hold the data
$resultArray = array();
$tempArray = array();
// Loop through each row in the result set
while($row = $result->fetch_object())
{
// Add each row into our results array
$tempArray = $row;
array_push($resultArray, $tempArray);
}
// Encode the array to JSON and output the results
echo json_encode($resultArray);
}
// Close connections
mysqli_close($dbConnection);
?>
最佳答案
该问题与托管提供商有关。我最初使用的提供程序安装了奇怪的安全协议(protocol),因此在切换后它工作完美,没有返回任何 JSON。
关于ios - Alamofire:失败响应序列化失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52948481/