json - 当某些值甚至不是 nil(缺失或不存在)时，我如何快速处理 JSON 对象

Question

大家好，我有一个 json 对象，存在不规则响应的问题，有时它不会发送我的模型中的一些键和值，例如:

struct GetComments: Codable {
   let name, surname: String
   let photoPath: String
   let commentid, comment, date: String
   let commentOwner: String
   let id : String
   let email: String
}

我尝试为模型提供一些初始值，如下所示，但它仍然崩溃:

struct GetComments: Codable {
   let name, surname: String = “”
   let photoPath: String = “”
   let commentid, comment, date: String = “”
   let commentOwner: String = “”
   let id : String = “”
   let email: String = “”
}

充满了我的 json 对象，例如:

{
   “name”:"Calvin",
   “surname”:“Harris”,
   “photoPath”: "https://image.flaticon.com/icons/png/128/181/181549.png",
   “commentid”: “ASHF579OTUJKDH475870987NBMVK”,
   “comment”: “hello everyone”,
   “date”: “11/06/2019",
   “commentOwner”: “Calvin Harris”,
   “id”: “LHKHOYIYU9OTUJKDH475870987NBMVK”,
   “email”: “calvin@test.com”
}

当我收到它时问题就开始了:

{
       “name”:“Calvin”,
       “surname”:“Harris”,
       “commentid”: “ASHF579OTUJKDH475870987NBMVK”,
       “comment”: “hello everyone”,
       “date”: “11/06/2019",
       “commentOwner”: “Calvin Harris”,
       “id”: “LHKHOYIYU9OTUJKDH475870987NBMVK”,
    }

Answer 1

只需将结构成员声明为可选，可以是nil

struct GetComments: Codable {
   let name, surname: String
   let photoPath: String? // can also be decoded as URL?
   let commentid, comment, date: String
   let commentOwner: String
   let id : String
   let email: String?
}