swift - 尝试将 NSPopupButton 的 `` `enabled ``` 属性绑定(bind)到复选框的状态

Question

使用 cocoa 绑定(bind)，我希望根据是否选中复选框来启用或禁用弹出按钮。

我以编程方式将复选框和弹出窗口添加到堆栈 View 中，如下所示:

  private func addCheckBoxes() {
        for period in String.BuildTimePeriod.allCases {
            let checkbox = NSButton(checkboxWithTitle: period.rawValue.capitalized, target: self, action: nil)
            checkbox.bind(.value, to: NSUserDefaultsController.shared, withKeyPath: "values.\(period.defaultsBoolKey.rawValue)", options: [NSBindingOption.continuouslyUpdatesValue: true])
            stackView.addArrangedSubview(checkbox)
            addPopUpToCheckbox(checkbox, period: period)
        }
    }

    private func addPopUpToCheckbox(_ checkbox: NSButton, period: String.BuildTimePeriod) {
        let popUp = NSPopUpButton(frame: checkbox.frame, pullsDown: false)
        let timeBlocks = String.TimeBlock.allCases.map() { $0.rawValue.capitalized }
        popUp.addItems(withTitles: timeBlocks)
        popUp.bind(.selectedValue, to: NSUserDefaultsController.shared, withKeyPath: "values.\(period.rawValue)", options: [NSBindingOption.continuouslyUpdatesValue: true])
        popUp.bind(.enabled, to: checkbox, withKeyPath: "state", options: [NSBindingOption.continuouslyUpdatesValue : true])
        stackView.addArrangedSubview(popUp)
    }

绑定(bind)在 Controller 的初始加载时起作用，但是，弹出窗口启用状态不会动态更改。想知道是否有人可以提供任何指导。

Answer 1

感谢@Willeke，我意识到这是因为我只是引用了“state”，而不是按钮所需的“cell.state”。