swift - 如何从函数中的结构访问该值？ swift

Question

我希望能够传入 garrett 或 allegany，并调用其中一个值，但我使用的点表示法给我 mdCounties.type 没有名为 County Transfer 的成员。但我确实创建了一个实例(加勒特和阿勒格尼)？？？

  struct mdCounties {
    var countyRecordation: Double = 0
    var countyTransfer: Double = 0
}

let garrett = mdCounties(countyRecordation: 7.0, countyTransfer: 1.0)
let allegany = mdCounties(countyRecordation: 6.50, countyTransfer: 0.005)

func mDtransferTaxCalc(purchasePrice: Double, split: Bool,mdCounties) -> Double {
    let userCountyTransfer = (purchasePrice) * mdCounties.countyTransfer

Answer 1

mdCounties 是您的类型。您需要该结构的实例才能访问其实例方法。您的函数参数也没有正确写入。改为这样做:

func mDtransferTaxCalc(purchasePrice: Double, split: Bool, counties: mdCounties) -> Double {
    let userCountyTransfer = (purchasePrice) * counties.countyTransfer
    return userCountyTransfer
}