这是一个粗略的示例(我正在处理的实际用例与 PHImageManager 的 requestImageForAsset: 函数的内部有关),但我正在寻找一种模式,允许您重新运行基于结果在完成 block 中。
Playground 代码:
private func subtractTen (value: Int, completion: (success: Bool, newVal: Int, [NSObject: AnyObject]?) -> Void) -> Int {
// This is private to represent a black box.
// In my personal use-case, it's actually a Foundation method
completion(success: (value - 10 >= 0), newVal: value - 10, nil)
return value - 10
}
func alwaysPositive (value: Int) -> Int {
var foo: Int
foo = subtractTen(value) { success, newVal, _ in
if success {
print ("yay")
} else {
// I need subtractTen re-run with a new input: newVal
// and I need the resulting value in the calling function
// (in this case, "foo")
print ("re-run subtractTen with newVal, and return the value to the parent function")
}
return
}
return foo
}
alwaysPositive(10)
您可以使用 1、2、9、10、11 等值运行alwaysPositive,以查看何时显示“重新运行”消息。
对于我想要做的事情有一个通用的 Swift 模式吗?
最佳答案
看看这段代码,也许它会对您正在寻找的内容有所帮助:
override func viewWillAppear(animated: Bool) {
rerunThis(0, callback: { (number_returned: Int, returned: Bool) in
println("returned: \(number_returned), \(returned)");
self.rerunThis(number_returned, callback: { (new_number_returned: Int, returned: Bool) in
println("new returned: \(new_number_returned), \(returned)");
});
});
}
func rerunThis(last_number: Int, callback: ((Int, Bool)->Void)) {
let new_value: Int = last_number+1;
var return_this: Bool = false;
if (new_value <= 1){
return_this = true;
}
callback(new_value, return_this);
}
关于Swift:如何根据完成 block 中的结果重新运行函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37125112/