java - 将密码正则表达式与相同的字符连续组合

Question

我有一个密码正则表达式，如下

^((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[!@#$%&*])).{0,100}$

我想添加正则表达式来验证这一点，并排除连续插入四个相同字符

我发现这个模式可以匹配 4 个相同的字符，但是我如何组合它们，并且这个模式应该检查是否有 4 个相同的字符，密码应该无效。

(.)\1{3}

Answer 1

这有效:

^((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[!@#$%&*]))((.)(?!\3{3})){0,100}$

说明:

^                     // beginning of string
(                     // begin capturing group #1 (this is actually unnecessary)
  (?=.*\d)            // must contain a digit
  (?=.*[a-z])         // must contain a lowercase letter
  (?=.*[A-Z])         // must contain an uppercase letter
  (?=.*[!@#$%&*])     // must contain a special character
)                     // end capturing group #1
(                     // begin capturing group #2: one character of password, for repetition quantifier
  (.)                 // capturing group #3: one character of password, for negative lookahead
  (?!\3{3})           // character is not followed by itself 3 times
)                     // end capturing group #2
{0,100}               // repeat group #2 up to 100 times
$                     // end of string