javascript - 如何在javascript中从ArrayBuffer获取Short值？

Question

我在java中有一个ByteBuffer，我从中写下前几个值，它们是:

[-112, -37, 96, -28, -16, -28, -64, -25, 112, -30, -112, -29, 48, -28, 48,
 -30, -48, -28, 32, -27, 80, -31, -112, -29, 80, -31, -96, -28, -96, -28, 
 -112, -30, -96, -30, -16, -27, 16, -28, 48, -27, -64, -32, -112, -30, -32,
 -29, etc ,...]

像 mybuffer.getShort() 这样的代码返回值 -9328、-7072 等...
根据Java API:

short java.nio.ByteBuffer.getShort()

用于读取短值的相对 get 方法。

Reads the next two bytes at this buffer's current position, composing them into a short value according to the current byte order, and then increments the position by two.

Returns:The short value at the buffer's current position

Throws:BufferUnderflowException - If there are fewer than two bytes remaining in this buffer.

到这里一切都很好，所以问题从这里开始，问题是如果我想在 javascript 中实现相同的目标，那么该怎么做？

我在javascript中使用ArrayBuffer，但是根据java API，他们做了一些计算，这非常令人困惑。

这是我的 JavaScript 代码:

var buf = new ArrayBuffer(res.length); // 2 bytes for each char
var bufView = new Uint16Array(buf); //buf is same as buffer in java ByteBuffer above.

for (var i = 0, strLen = res.length; i < strLen; i++) {
    bufView[i] = res.charCodeAt(i);
}

Answer 1

只是需要同样的东西，但很失望没有提供答案:D

玩了一下Scala，然后跳到Java，终于得到了这个 (当然这符合我的需求，Java的实现有不同的选择..)

const getShort = (a,b) => a << 8 | b << 0

如果你有一个 Uint8Array([1,2,3,4,5,6])

const uiArr = new Uint8Array([1,2,3,4,5,6])

并且您想要获得第一个短值，只需传递数组中的前两个值

const firstShort = getShort(uiArr[1], uiArr[0]) // in my case little endian 
const secondShort = getShort(uiArr[3], uiArr[2])