java - JAVA中使用反向引用的递归组捕获正则表达式

Question

我试图在字符串中递归地捕获多个组，同时还使用对正则表达式中的组的反向引用。即使我使用模式和匹配器以及“while(matcher.find())”循环，它仍然只捕获最后一个实例而不是所有实例。就我而言，唯一可能的标签是 、、、、、、、。由于这些是格式化标签，我需要捕获:

1. 标签之外的任何文本(以便我可以将其格式化为“正常”文本，并且我将通过捕获一个组中标签之前的任何文本，同时捕获另一组中的标签本身来实现此目的，并且作为我遍历所有出现的事件，删除从原始字符串中捕获的所有内容；如果最后留下任何文本，我会将其格式化为“正常”文本)
2. 标签的“名称”，以便我知道我将如何拥有 设置标签内文本的格式
3. 标签的文本内容将根据标签名称及其关联规则进行格式化

这是我的示例代码:

        String currentText = "the man said:<pof>“This one, at last, is bone of my bones</pof><poi>and flesh of my flesh;</poi><po>This one shall be called ‘woman,’</po><poil>for out of man this one has been taken.”</poil>";
        String remainingText = currentText;

        //first check if our string even has any kind of xml tag, because if not we will just format the whole string as "normal" text
        if(currentText.matches("(?su).*<[/]{0,1}(?:sm|po)[f|l|s|i|3]{0,1}[f|l]{0,1}>.*"))
        {                
            //an opening or closing tag has been found, so let us start our pattern captures
            //I am using a backreference \\2 to make sure the closing tag is the same as the opening tag
            Pattern pattern1 = Pattern.compile("(.*)<((sm|po)[f|l|s|i|3]{0,1}[f|l]{0,1})>(.*?)</\\2>",Pattern.UNICODE_CHARACTER_CLASS);
            Matcher matcher1 = pattern1.matcher(currentText);                
            int iteration = 0;
            while(matcher1.find()){
                System.out.print("Iteration ");
                System.out.println(++iteration);
                System.out.println("group1:"+matcher1.group(1));
                System.out.println("group2:"+matcher1.group(2));
                System.out.println("group3:"+matcher1.group(3));
                System.out.println("group4:"+matcher1.group(4));

                if(matcher1.group(1) != null && matcher1.group(1).isEmpty() == false)
                {
                    m_xText.insertString(xTextRange, matcher1.group(1), false);
                    remainingText = remainingText.replaceFirst(matcher1.group(1), "");
                }
                if(matcher1.group(4) != null && matcher1.group(4).isEmpty() == false)
                {
                    switch (matcher1.group(2)) {
                        case "pof": [...]
                        case "pos": [...]
                        case "poif": [...]
                        case "po": [...]
                        case "poi": [...]
                        case "pol": [...]
                        case "poil": [...]
                        case "sm": [...]
                    }
                    remainingText = remainingText.replaceFirst("<"+matcher1.group(2)+">"+matcher1.group(4)+"</"+matcher1.group(2)+">", "");
                }
            }

System.out.println 仅在我的控制台中输出一次，结果如下:

Iteration 1:
  group1:the man said:<pof>“This one, at last, is bone of my bones</pof><poi>and flesh of my flesh;</poi><po>This one shall be called ‘woman,’</po>; 
  group2:poil
  group3:po
  group4:for out of man this one has been taken.”

组 3 将被忽略，唯一有用的组是 1、2 和 4(组 3 是组 2 的一部分)。为什么这只捕获最后一个标签实例“poil”，而不捕获前面的“pof”、“poi”和“po”标签？

我希望看到的输出是这样的:

Iteration 1:
  group1:the man said:
  group2:pof
  group3:po
  group4:“This one, at last, is bone of my bones

Iteration 2:
  group1:
  group2:poi
  group3:po
  group4:and flesh of my flesh;

Iteration 3:
  group1:
  group2:po
  group3:po
  group4:This one shall be called ‘woman,’

Iteration 3:
  group1:
  group2:poil
  group3:po
  group4:for out of man this one has been taken.”

Answer 1

我刚刚找到了这个问题的答案，它只需要在第一个捕获中使用非贪婪量词，就像我在第四个捕获组中一样。这完全按照需要工作:

Pattern pattern1 = Pattern.compile("(.*?)<((sm|po)[f|l|s|i|3]{0,1}[f|l]{0,1})>(.*?)</\\2>",Pattern.UNICODE_CHARACTER_CLASS);