Java xml 解析。通过一个函数调用深入浏览 xml 文件

Question

我有以下 xml 文件

<basicCallInformation>
   <chargeableSubscriber>
       <simChargeableSubscriber>
           <imsi>26 20 32 23 16 62 80 3F</imsi>
           <msisdn>49 16 32 70 04 00</msisdn>
       </simChargeableSubscriber>
   </chargeableSubscriber>
</basicCallInformation>

如果可能的话，我想直接转到节点“imsi”和“msisdn”以通过一个函数调用来获取它们的值。像这样的事情

basicCallInformationNode.getNode('chargeableSubscriber/simChargeableSubscriber/imsi'); //something like this can be done in PLSQL

有没有办法在Java中做到这一点？有什么解决办法吗？

附注我正在使用 DOM 解析器

Answer 1

当然，

        XPath.evaluate(
    "/basicCallInformation/chargeableSubscriber/simChargeableSubscriber/imsi |
     /basicCallInformation/chargeableSubscriber/simChargeableSubscriber/msisdn"
        );