我有一个包含订单日期和订单值(value)的订单列表。如何按订单日期分组并计算每个订单日期的总订单值(value)。我怎样才能在 Google Guava 中实现这一目标?如果事情变得复杂......我如何在 Java 集合中实现这一点?
订购POJO
Date date;
Integer Value;
Util.java
ListMultimap<Date, Integer> listMultiMap = ArrayListMultimap.create();
for(Order o : orders){
listMultiMap.put(o.date, o.value);
}
//Now how do I iterate this listMultiMap and calculate the total value?
最佳答案
我认为 Guava 不一定是这里最好的工具...也不是任何法线贴图,就此而言:如果您有大量订单,您应该考虑使用 Java8 Streams,这将使您能够并行化你的计算。它还将对原始类型(int 与 Integer)进行优化...
无论如何,对于您描述的特定用例并遵循您发布的起始代码,这里是一个潜在的解决方案(使用 LocalDate 而不是 Date 只是因为它更方便):
@Test
public void test(){
// Basic test data
Order today1 = new Order(LocalDate.now(),1);
Order today2 = new Order(LocalDate.now(),2);
Order today3 = new Order(LocalDate.now(),5);
Order tomorrow1 = new Order(LocalDate.now().plusDays(1),2);
Order yesterday1 = new Order(LocalDate.now().minusDays(1),5);
Order yesterday2 = new Order(LocalDate.now().minusDays(1),4);
List<Order> list = Lists.newArrayList(today1,today2,today3,tomorrow1,yesterday1,yesterday2);
// Setup multimap and fill it with Orders
ListMultimap<LocalDate, Integer> mm = ArrayListMultimap.create();
for(Order o : list){
mm.put(o.date,o.value);
}
// At this point, all you need to do is, for each date "bucket", sum up all values.
Map<LocalDate, Integer> resultMap = Maps.newHashMap();
for(LocalDate d : mm.keySet()){
List<Integer> values = mm.get(d);
int valuesSum = 0;
for(int i : values){
valuesSum += i;
}
resultMap.put(d,valuesSum);
}
/*
* Result map should contain:
* today -> 8
* tomorrow -> 2
* yesterday -> 9
* */
assertThat(resultMap.size(), is(3));
assertThat(resultMap.get(LocalDate.now()), is(8));
assertThat(resultMap.get(LocalDate.now().minusDays(1)), is(9));
assertThat(resultMap.get(LocalDate.now().plusDays(1)), is(2));
}
关于java - 当键从列表派生时如何迭代 Guava MultiMap,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33040862/