java - MVC 和带有 Set<> 的对象

Question

我有 2 个映射到 Hibernate 的类。
1. 类实现账户
2.该类实现账户类型。
重要!一个账户可以有多种类型。

 Account.class
    @Entity
    @Table(name = "dp_account",
            uniqueConstraints={@UniqueConstraint(columnNames={"id"})})
        public class Account {

            @Id
            @Column(name="id", nullable = false, unique = true, length = 11)
            @GeneratedValue(strategy = GenerationType.AUTO)
            private long id;

            @Column(name = "price", nullable = false)
            private int price;

            @Column(name = "customer_id", nullable = false, unique = true, length = 11)
            private long customerId;

            @Column(name = "customer", length = 100, nullable = false, unique = true)
            private String customer;

            @Column(name = "comment", length = 1000)
            private String comment;

            @Column(name = "date", columnDefinition="TIMESTAMP")
            @Temporal(TemporalType.TIMESTAMP)
            private Date date;

            @Column(name = "is_deleted", nullable = false)
            private boolean deleted = false;

            @ManyToMany(fetch = FetchType.EAGER, targetEntity = AccountType.class, cascade = { CascadeType.ALL })
            @JoinTable(name = "account_accountType",
                    joinColumns = { @JoinColumn(name = "account_id") },
                    inverseJoinColumns = { @JoinColumn(name = "type_id") })
            private Set<AccountType> accountTypes;
        // дальше конструкторы и геттеры/сеттеры
        }

帐户类型的本质，包括名称、描述、ID 和所有者姓名。

    AccountType.class
    @Entity
    @Table(name = "account_type")
    public class AccountType {
        private static final Long serialVersionUID = -4727727495060874301L;

        @Id
        @Column(name = "id")
        @GeneratedValue(strategy = GenerationType.AUTO)
        private long id;

        @Column(name = "name", length = 25, nullable = false, unique = true)
        private String name;

        @Column(name = "description", length = 255)
        private String description;

        @Column(name = "user_login", length = 45, nullable = false, unique = true)
        private String login;
   //дальше геттеры/сеттеры и конструкторы
}

问题是 - 有一个页面，我可以在其中填写表格来创建帐户 ( Account.class )，我愿意 multiple select , 填写账户类型 (AccountType.class)。 Account.class 有字段 Set<AccountType> accountTypes ，其中每个帐户都包含一个类型列表。 (这是我试图填写的列表，然后在 MVC Controller 中传递 Account.class)。但是在 Controller 中我什至没有收到 400 错误。经过多次测试，我意识到 Spring MVC 不会绑定(bind)我的列表。我想知道如何做到这一点？

MVC Controller :

@RequestMapping(value = "/account/addAccount", method = RequestMethod.POST)
    public void addAccount(@ModelAttribute("accountAttribute") Account account) {
        System.out.println("Account on the top");
        System.out.println(account);
        ServiceFactory.getInstance().getAccountService().addAccount(account);
    }

JSP:

<div style="margin-top: 40px">
            <form:form action="${pageContext.request.contextPath}/account/addAccount" method="post" modelAttribute="accountAttribute">

                <label>
                    Сумма: <input type="number" name="price">
                </label>
                <br> <br>

                <label>
                    Категория:
                    <select multiple name="accountTypes">
                        <c:forEach items="${accountTypes}" var="accountType">
                        <option value="${accountType.name}">${accountType.name}</option>
                        </c:forEach>
                    </select>
                </label>
                <br><br>

                <label>Комментарий:
                    <br> <br>
                    <textarea name="comment" rows="5" cols="30"></textarea>
                </label>
                <br><br>

                <input type="submit" value="Внести">

            </form:form>
        </div>

截图示例:

更新:

@RequestMapping(value = "/welcome", method = RequestMethod.GET)
    public ModelAndView welcomePage() {
        ModelAndView model = new ModelAndView();
        List<GrantedAuthority> grantedAuthorityList = (List<GrantedAuthority>) SecurityContextHolder.getContext().getAuthentication().getAuthorities();
        Authentication authentication = SecurityContextHolder.getContext().getAuthentication();
        String login = authentication.getName();
        if (grantedAuthorityList.contains(new SimpleGrantedAuthority("ROLE_ADMIN"))) {
            model.setViewName("admin");
        } else {
            List<AccountType> accountTypes = ServiceFactory.getInstance().getAccountService().getAllAccountTypeByLogin(login);
            model.addObject("accountTypes", accountTypes);
            model.setViewName("user");
        }
        return model;
    }

Answer 1

您正在使用 html select 元素，但您需要做的是使用 spring 标签库的 select 即:

<form:select path="accountTypes" multiple="true">
  <form:options items="${accountTypes}"/>
</form:select>

这样 spring 就会绑定(bind) Controller 中的值。

尝试使用这个

@RequestMapping(value = "/welcome", method = RequestMethod.GET)
public ModelAndView welcomePage() {
    ModelAndView model = new ModelAndView();
    List<GrantedAuthority> grantedAuthorityList = (List<GrantedAuthority>) SecurityContextHolder.getContext().getAuthentication().getAuthorities();
    Authentication authentication = SecurityContextHolder.getContext().getAuthentication();
    String login = authentication.getName();
    if (grantedAuthorityList.contains(new SimpleGrantedAuthority("ROLE_ADMIN"))) {
        model.setViewName("admin");
    } else {
        List<AccountType> accountTypes = ServiceFactory.getInstance().getAccountService().getAllAccountTypeByLogin(login);
        model.addObject("accountTypes", accountTypes);
        model.setViewName("user");
//Add here
model.addObject("accountAttribute", new Account());
    }
    return model;
}