java - 如何在不导入任何 java 库的情况下使直方图更加 OOPy？

Question

我正在为学校制作一个直方图项目，该项目循环遍历一个数组，并在每次给定数字部分出现一个数字时创建一个 * 。输出应如下所示:

1-10   | *****
11-20  | ****
21-30  | *
31-40  | ***
41-50  | *
51-60  | *
61-70  | *
71-80  | 
81-90  | *
91-100 | ********

对于一个数组:

int 数组[] = {19, 4, 15, 7, 11, 9, 13, 5, 45, 56, 1, 67, 90, 98, 32, 36, 33, 25, 99, 95, 97 , 98, 92, 94, 93, 105};

我正在尝试找出一种方法使这段代码更加面向对象。但是，我想不出办法。

这是我的代码:

public class Main {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        // TODO code application logic here
        int array[] = {19, 4, 15, 7, 11, 9, 13, 5, 45, 56, 1, 67, 90, 98, 32, 36, 33, 25, 99, 95, 97, 98, 92, 94, 93, 105};
        histogram(array);
    } 
    public static void histogram(int[] input) {
        String output1 = new String ();
        String output2 = new String ();
        String output3 = new String ();
        String output4 = new String ();
        String output5 = new String ();
        String output6 = new String ();
        String output7 = new String ();
        String output8 = new String ();
        String output9 = new String ();
        String output10 = new String ();
        for (int x = 0; x < input.length; x++) {
            if (input[x] <= 100) {
                if (input[x] >= 1 && input [x] <= 10) output1 += "*";
                if (input[x] >= 11 && input [x] <= 20) output2 += "*";
                if (input[x] >= 21 && input [x] <= 30) output3 += "*";
                if (input[x] >= 31 && input [x] <= 40) output4 += "*";
                if (input[x] >= 41 && input [x] <= 50) output5 += "*";
                if (input[x] >= 51 && input [x] <= 60) output6 += "*";
                if (input[x] >= 61 && input [x] <= 70) output7 += "*";
                if (input[x] >= 71 && input [x] <= 80) output8 += "*";
                if (input[x] >= 81 && input [x] <= 90) output9 += "*";
                if (input[x] >= 91 && input [x] <= 100) output10 += "*";
            }
            else {
                break;
            }
        }
        System.out.println("1-10   | " + output1);
        System.out.println("11-20  | " + output2);
        System.out.println("21-30  | " + output3);
        System.out.println("31-40  | " + output4);
        System.out.println("41-50  | " + output5);
        System.out.println("51-60  | " + output6);
        System.out.println("61-70  | " + output7);
        System.out.println("71-80  | " + output8);
        System.out.println("81-90  | " + output9);
        System.out.println("91-100 | " + output10);

    }
}

Answer 1

既然可以把事情变得复杂，为什么还要把事情变得简单呢？

public static void main(String[] args) {         
   int array[] = {19, 4, 15, 7, 11, 9, 13, 5, 45, 56, 1, 67, 90, 98, 32, 36, 33, 25, 99, 95, 97, 98, 92, 94, 93, 105}; 
   histogram(array);
}
public static void histogram(int[] input) {
    for(int i = 1; i<101; i = i+10){
        System.out.print(i + "-" + (i+9) + "\t| ");
        for(int j = 0; j< input.length; j++){
            if(input[j] >= i && input[j] < i+10)
            System.out.print("*");
        }
        System.out.println();
    }
}